compute iou function confusion

def compute_iou(img1, img2):

img1 = np.array(img1)
img2 = np.array(img2)

if img1.shape[0] != img2.shape[0]:
    raise ValueError("Shape mismatch: the number of images mismatch.")
IoU = np.zeros( (img1.shape[0],), dtype=np.float32)
for i in range(img1.shape[0]):
    im1 = np.squeeze(img1[i]>0.5)
    im2 = np.squeeze(img2[i]>0.5)

    if im1.shape != im2.shape:
        raise ValueError("Shape mismatch: im1 and im2 must have the same shape.")

    # Compute Dice coefficient
    intersection = np.logical_and(im1, im2)

    if im1.sum() + im2.sum() == 0:
        IoU[i] = 100
    else:
        **IoU[i] = 2. * intersection.sum() * 100.0 / (im1.sum() + im2.sum())**
    #database.display_image_mask_pairs(im1, im2)

return IoU

Is this bold line correct will it have 2 or not

MrGiovanni / UNetPlusPlus

compute iou function confusion #45