In the UI, if you try to create a node of a type that the interface displays as having space in it (e.g Named Thing, Sequence Variant, etc), including the space between the words breaks the string matching. Typing the label with an underscore, as it appears in the db, (named_thing) does return the category.
In the UI, if you try to create a node of a type that the interface displays as having space in it (e.g Named Thing, Sequence Variant, etc), including the space between the words breaks the string matching. Typing the label with an underscore, as it appears in the db, (named_thing) does return the category.