Closed stevengj closed 5 months ago
In particular, I would:
Note, as we've discussed previously, that when you compute the contribution from each m, because the different m's are orthogonal when you integrate over φ, and the integral over φ for a single m just gives a 2π factor, you can effectively evaluate P(θ) only at φ=0 for each m and then just sum the powers timse 2π.
It might be nice to extend this tutorial to show how a similar calculation could be performed in cylindrical coordinates, e.g. for random currents distributed uniformly over a disk.
Even if you were doing the calculation in Cartesian coordinates, you would still only need one dipole source per radius r. Given its emitted power P(r), the total emitted power would be ∫P(r) 2πr dr — note the r factor! To do the same thing in cylindrical coordinates, you additionally may need to be careful about the normalization of the cylindrical "dipole" (actually ring) sources.