NickWaterton
commented
6 years ago This is (another) python 3 slight incompatibility. Python 3 receives string arrays as type "bytes" - Python 2.7 receives these are type "string".
The json library expects to receive a string, not a byte array as Python 3 produces. You would think the built in libraries would accept the results of other built in libraries in Python 3 (like Python 2.7 does), but not so easy. Python 3.6 works, but Python 3.5 does not.
There is a lot of debate about this sort of pointless incompatibility, but the fix is to change line 54 of the password.py module from:
parsedMsg = json.loads(udp_data)
To:
parsedMsg = json.loads(udp_data.decode('utf-8'))
The program was originally written for Python 2.7, and it's hard to make it work with Python 3.X as they keep changing this type of compatibility in each version of Python 3 (which is why I don't use it...).
You can read the debate here if you want https://bugs.python.org/issue10976
Unfortunately, you are likely to run into more of these kinds of problems in the code, as it works in Python 2.7 and Python 3.6, but Python 3.5 has various problems including the json deserializing error you have already found.
You could always run it as a python 2 program python2 roomba.py I think ubuntu 16.04 has both python 2 and python 3 as stock. In fact I thought python 2 was still the default.
starlightknight
Hi, When I try to run the quick start, I get the output shown below. It seems to scan and find my Roombas correctly, but fails to parse the responses even though it is receiving them, and thus fails out thinking it didn't find any. OS is Linux Mint 18.2 (Ubuntu 16.04 base).