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Softky et. al. find that
Shadlen et. al. find that
Excitatory synapses outnumber inhibitory synapses by 6:1, but inhibitory synapses/neurons have
Direct evidence is found by Xue et. al.
Based on Shadlen et. al., Vreeswijk et. al. investigates whether needs fine-tuning of parameters and computational benefits.
$\Theta(.)$ is Heaviside function.
$$ \sigma{k}^{i}(t)=\Theta\left(u{k}^{i}(t)\right) $$
$$ u{k}^{i}(t)=\Sigma{l=1}^{2}\Sigma{j=1}^{N{l}}J{kl}^{ij}\sigma{l}^{j}(t)+u{k}^{0}-\theta{k} $$
$$ J{EE}=J{IE}=1; J{E}=-J{EI}; J{I}=-J{II} $$
$$ m{k}^{i}(t)=\left<\sigma{k}^{i}(t)\right> $$
$$ u{E}=(Em{0}+m{E}-J{E}m{I})\sqrt{K}-\theta_{E} $$
$$ u{I}=(Im{0}+m{E}-J{I}m{I})\sqrt{K}-\theta{I} $$
Balanced state necessary condition: $0 < m < 1$ even when $K$ is large.
$$ Em{0}+m{E}-J{E}m{I}=O(\frac{1}{\sqrt{K}}) $$
$$ Im{0}+m{E}-J{I}m{I}=O(\frac{1}{\sqrt{K}}) $$
Then, we get
$$ m{E}=\frac{J{I}E-J{E}I}{J{E}-J{I}}m{0}=A{E}m{0} $$
$$ m{I}=\frac{E-I}{J{E}-J{I}}m{0}=A{I}m{0} $$
And the requirements are
$$ m{E}>0; m{I} > 0 $$
$$ \frac{E}{I}>\frac{J{E}}{J{I}}>1 $$
$$ J_{E}>1 $$
Dynamics (Ginzhurg \& Sompolinsky, 1994)
$$ \tau{k}\frac{d}{dt}m{k}^{i}(t)=-m{k}^{i}(t)+\Theta\left(u{k}^{i}(t)\right) $$
Rewriting $u{k}^{i}(t)$ , where $p{l}(n{l})$ is the probability of receiving $n{l}$ spikes from population $l$.
Now, we get the following conclusions
Huang et. al. find that
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