Now that we have .deblaze() working, we are left with a Rayleigh-Jeans looking spectrum from order-to-order. Let's add a method to divide this out with a black body, which should render a nearly flattened spectrum ideal for cross-correlation with a template.
Now that we have
.deblaze()working, we are left with a Rayleigh-Jeans looking spectrum from order-to-order. Let's add a method to divide this out with a black body, which should render a nearly flattened spectrum ideal for cross-correlation with a template.