PandABlocks / PandABlocks-ioc

Create an IOC from a PandA
Apache License 2.0
1 stars 5 forks source link

record creation attempted for non-defined sequencer tables #54

Closed evalott100 closed 1 year ago

evalott100 commented 1 year ago

If SEQ2 isn't defined for the panda (in the web gui) then in IocRecordFactory::_make_table we'll have an _all_values_dict["SEQ2:TABLE"] of [], and SEQ2:TABLE:TRIGGER will be 0 instead of a string enum value. This causes a failure when building the ioc.