Open Jawmo opened 5 years ago
I just do a for loop looping over all the clients and selecting only the one i want. Here's my function:
def sendMessageToClient(name, message):
targetClient = None
for oneClient in server.clients:
if oneClient['id'] == name:
targetClient = oneClient
break
if targetClient is not None:
server.send_message(targetClient, message)
Hope it helps
This is a bad design decision at the time - using a list instead of a dict.
The workaround is to loop through the clients and once you find your client, use the handler handler.send_text
Maybe there should be a server.clients_dict
or something (in addition to the existing, to keep compatibility)?
Maybe there should be a
server.clients_dict
or something (in addition to the existing, to keep compatibility)?
Yes, probably a clients_by_id
with client ID as key. But not something I have the time currently to work on unfortunately
I might pick this up. Shouldn't be too difficult.
I just do a for loop looping over all the clients and selecting only the one i want. Here's my function:
def sendMessageToClient(name, message): targetClient = None for oneClient in server.clients: if oneClient['id'] == name: targetClient = oneClient break if targetClient is not None: server.send_message(targetClient, message)
Hope it helps
Thanks for that. It helped me to solve this problem.
I noticed that you have instructions to send to a specific client, but when I print our the value of "client", I just get back the current user's information. If I have to use "client" when I use send_message(), how do I actually specify the client ID?
I have to use: send_message(client, "message here.)
If I change "client" to "client['id']" or something, it won't work. How do you actually specify which use it should go to?