Closed shlff closed 4 years ago
Good morning @jstac , this PR corrects some errors in the proof of Exercise 3 of lecture markov_prop:
P (x_{n-1}, x_n ) \mathbf P_\psi^n(x_0, x_1, \ldots, x_{n-1}) = P (x_n, x_{n+1} ) \psi(x_0) P(x_0, x_1) \times \cdots \times P(x_{n-1}, x_{n-1}) --->>>
P (x_{n-1}, x_n ) \mathbf P_\psi^n(x_0, x_1, \ldots, x_{n-1}) = P (x_n, x_{n+1} ) \psi(x_0) P(x_0, x_1) \times \cdots \times P(x_{n-1}, x_{n-1})
P (x_{n-1}, x_n ) \mathbf P_\psi^{n-1}(x_0, x_1, \ldots, x_{n-1}) = P (x_{n-1}, x_n ) \psi(x_0) P(x_0, x_1) \times \cdots \times P(x_{n-2}, x_{n-1})
Nice work, thanks @shlff .
Good morning @jstac , this PR corrects some errors in the proof of Exercise 3 of lecture markov_prop:
P (x_{n-1}, x_n ) \mathbf P_\psi^n(x_0, x_1, \ldots, x_{n-1}) = P (x_n, x_{n+1} ) \psi(x_0) P(x_0, x_1) \times \cdots \times P(x_{n-1}, x_{n-1})
--->>>P (x_{n-1}, x_n ) \mathbf P_\psi^{n-1}(x_0, x_1, \ldots, x_{n-1}) = P (x_{n-1}, x_n ) \psi(x_0) P(x_0, x_1) \times \cdots \times P(x_{n-2}, x_{n-1})