Closed Quelklef closed 2 years ago
See below:
│ 1. [a] assumed │ 2. Pa assumed ├────────── │ 3. ∃xPa ∃I:2[a→x]
The justification given is ∃I:2[a→x], but should be ∃I:2[a→a]
∃I:2[a→x]
∃I:2[a→a]
Meh, not a bug, just confusing.
Line 3 was indeed concluded from line 2 via a variable replacement a→x, it's just that 0 as were replaced with x
a→x
a
x
Not a big deal; closing
See below:
The justification given is
∃I:2[a→x]
, but should be∃I:2[a→a]