Closed xue160709 closed 4 months ago
When fetching timeline, you give the id of the user as a parameter, not the username (the same is shown in the error details: `id must be a number string')
To get the id, fetch the details of the user first using user.details
method. Then use the id from the details to fetch timeline.
When fetching timeline, you give the id of the user as a parameter, not the username (the same is shown in the error details: `id must be a number string')获取时间线时,您将用户的 id 作为参数提供,而不是用户名(错误详细信息中显示的内容相同:“id 必须是数字字符串”)
To get the id, fetch the details of the user first using
user.details
method. Then use the id from the details to fetch timeline.要获取 id,请首先使用user.details
方法获取用户的详细信息。然后使用详细信息中的 id 来获取时间线。
Perfect solution! Thank you for your help, have a good day!
Thank you for your open source project! Currently I am encountering a problem during use
The error message is like this, how should I solve it? Or is this a bug?