Open mariuszi28cg opened 7 months ago
This is a good integral for the rational part of Bronstein's algorithm.
-- Rubi does not have a rule for this type of integral.
-- Mathematica does not implement Bronstein's algorithm for the mixed transcendental/algebraic case of the Risch algorithm.
I tried:
Int[((x^2 - 2)Exp[x])/((x - 1)Sqrt[1 - x^2]), x]
give me:
Int[E^x/Sqrt[1 - x^2], x] + Int[E^x/((1 - x) Sqrt[1 - x^2]), x] + Int[(E^x x)/Sqrt[1 - x^2], x]
but the answer is: (E^x (1 + x))/Sqrt[1 - x^2]
Mathematica can't compute it's very strange. Maple can.
Thanks.