RuleBasedIntegration / Rubi

Rubi for Mathematica
http://rulebasedintegration.org
MIT License
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Issue in Hard Integral #50

Open mariuszi28cg opened 7 months ago

mariuszi28cg commented 7 months ago

I tried:

Int[((x^2 - 2)Exp[x])/((x - 1)Sqrt[1 - x^2]), x]

give me:

Int[E^x/Sqrt[1 - x^2], x] + Int[E^x/((1 - x) Sqrt[1 - x^2]), x] + Int[(E^x x)/Sqrt[1 - x^2], x]

but the answer is: (E^x (1 + x))/Sqrt[1 - x^2]

Mathematica can't compute it's very strange. Maple can.

Thanks.

stblake commented 7 months ago

This is a good integral for the rational part of Bronstein's algorithm.

-- Rubi does not have a rule for this type of integral.

-- Mathematica does not implement Bronstein's algorithm for the mixed transcendental/algebraic case of the Risch algorithm.