Closed aliceesiee closed 2 years ago
Hello,
Well, you can probably make a loop (limited to q.nbRecs
) as you said using q.peekIdx
method to get every values to check.
But... a queue is not a list of elements, it is designed to be used as FIFO
or LIFO
, thus you can peek records to see if new record has to be stored in the queue, but you can't remove a record at any desired index.
Some kind of workaround for you would be flushing the whole queue (with q.flush
), or if in need of a circular buffer, using FIFO
implementation with overwrite=true
might work too (without the need to pull items from queue).
Please keep in mind an issue tracker is not a place to ask for implementation help (there are lots of forums for that (eg. stack exchange)) but to raise bugs/issues or ask for improvements / new functionalities.
Regards, SMFSW
Thanks for the answer and sorry for the misusing of the issue tracker !
Glad if I was able to help!
If needed, my libraries includes a contact email in README.md
.
Closing the issue for now,
Regards, SMFSW
Hello,
I would like to get the minimal value of a queue, because I am trying to modify this code https://github.com/Seeed-Studio/Seeed_Arduino_Linechart/blob/master/examples/basic/basic.ino I thought about writing a for loop with an if loop inside to compare each element but I don't manage to get the value inside the queue. I have tried like the vectors data[i] where data is a std::queue type and i the index.
Does anyone could give me some help?
Best regards,
Alice