Deprecation fix

[ChrisRackauckas]

Chris Rackauckas Sep 7th at 7:48 PM (construct(::Type{T}, nodes::Tuple{Vararg{<:AbstractMultiScaleArray}}, args...) where {T <: AbstractMultiScaleArray}) = __construct(T, nodes, eltype(T)[], args...)

(construct(::Type{T}, nodes::Tuple{Vararg{<:AbstractMultiScaleArray}}, values, args...) where {T <: AbstractMultiScaleArray}) = __construct(T, nodes, values, args...) gives: ERROR: LoadError: Wrapping Vararg directly in UnionAll is deprecated (wrap the tuple instead). You may need to write f(x::Vararg{T}) rather than f(x::Vararg{<:T}) or f(x::Vararg{T}) where T instead of f(x::Vararg{T} where T). Stacktrace: How do I handle this case? 8 replies

Oscar Smith Sep 7th at 7:55 PM Vararg{AbstractMultiScaleArray} 7:57 julia> Tuple{Int} <: Tuple{Vararg{Integer}} true

Chris Rackauckas Sep 7th at 9:02 PM ERROR: LoadError: ArgumentError: Vararg on non-final argument in method definition for construct at /home/runner/work/MultiScaleArrays.jl/MultiScaleArrays.jl/src/shape_construction.jl:53

Oscar Smith Sep 7th at 9:06 PM wait, this signature was ever valid? 9:07 how is it supposed to choose between nodes and args? 9:07 @jeffbezanson look at this horribleness Saved for later • Due 1 month ago

Jeff Bezanson Sep 10th at 3:57 PM The error message is unhelpful here since it's showing a random example rather than what you actually did. In this case you'd need nodes::Tuple{Vararg{T<:S}} where T, just put the where outside the tuple instead of only outside the vararg.

Chris Rackauckas Today at 4:46 AM @Oscar Smith can you help unblock this? I don't quite understand this.

[ChrisRackauckas]

@oscardssmith I assigned you since I have no idea what to do with this, but it's blocking downstream.