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Write about quantum minimum finding subroutines #27

Closed github-actions[bot] closed 3 years ago

github-actions[bot] commented 3 years ago

Write about quantum minimum finding subroutines

Amplitude amplification and estimation has been generalized to minimum finding procedure

where they retain the quadratic speedup of the original technique.

It would be good to have those subroutine included here, with a general expaination of the

idea of the proof used behind the algorithm

https://github.com/Scinawa/quantumalgorithms.org/blob/502053e2e37f92e1da9791ae71f9a5f014a34b2c/toolbox.Rmd#L19

author: "scinawa"
date: "2/21/2021"
output: html_document
---

# A useful toolbox

## Finding the minimum {#subsec:findmin}

```{lemma, find-minimum-orig, name="Quanutum minimum finding [@durr1996quantum]"}
Given quantum access to a vector $u \in [0,1]^N$ via the operation $\ket j \ket{\bar 0} \to \ket j \ket{ u_j}$ on $\Ord{\log N}$ qubits, where $u_j$ is encoded to additive accuracy $\Ord{1/N}$. Then, we can find the minimum $u_{\min} = \min_{j\in[N]}  u_j$ with success probability $1-\delta$ with $\Ord{\sqrt N \log \left (\frac{1}{\delta}\right) }$ queries and $\tOrd{\sqrt N  \log \left( \frac{1}{\delta}\right )}$ quantum gates.

Quantum linear algebra {#subsec:linearalgebra}

In our algorithms, we will also use subroutines for quantum linear algebra. From the first work of \cite{HarrowHassidim2009HHL} (known in the literature as HHL algorithm) that proposed a quantum algorithm for matrix inversion, a lot of progress has been made. In this section, we briefly recall some of the results in quantum linear algebra. We conclude by citing the state-of-the art techniques for performing not only matrix inversion and matrix multiplication, but also for applying a certain class of functions to the singular values of a matrix. A notable result after HHL was the ability to perform a quantum version of the singular value decomposition. This idea is detailed in the following theorem.

Let $M \in \mathbb{R}^{n \times d}$  be a matrix with singular value decomposition $M =\sum_{i} \sigma_i u_i v_i^T$ for which we have quantum access. Let $\varepsilon > 0$ the precision parameter. There is an algorithm with running time $\tilde{O}(\mu(M)/\varepsilon)$ that performs the mapping $\sum_{i} \alpha_i \ket{v_i} \to \sum_{i}\alpha_i \ket{v_i}  \ket{\tilde{\sigma}_i}$, where $\tilde{\sigma_i} - \sigma_i | \leq \varepsilon$ for all $i$ with probability at least $1-1/poly(n)$.

Recall that quantum access to a matrix is defined in theorem \@ref(def:KP-trees), and the parameter $\mu$ is defined in definition \@ref(def:mu). The relevance of theorem \@ref(thm:sve-theorem) for quantum machine learning is the following: if we are able to estimate the singular values of a matrix, then we can perform a conditional rotation controlled by these singular values and hence perform a variety of linear algebraic operations, including matrix inversion, matrix multiplication or projection onto a subspace. Based on this result, quantum linear algebra was done using the theorem stated below.

Let $M := \sum_{i} \sigma_iu_iv_i^T \in \mathbb{R}^{d \times d}$ such that $\norm{M}_2 = 1$, and a vector $x \in \mathbb{R}^d$ for which we have quantum access. There exist quantum algorithms that with probability at least $1-1/poly(d)$ return

- a state $\ket{z}$ such that $| \ket{z} - \ket{Mx}| \leq \epsilon$ in time $\tilde{O}(\kappa^2(M)\mu(M)/\epsilon)$
- a state $\ket{z}$ such that $|\ket{z} - \ket{M^{-1}x}| \leq \epsilon$ in time $\tilde{O}(\kappa^2(M)\mu(M)/\epsilon)$
- a state $\ket{M_{\leq \theta, \delta}^+M_{\leq \theta, \delta}x}$  in time $\tilde{O}(\frac{ \mu(M) \norm{x}}{\delta \theta \norm{M^{+}_{\leq \theta, \delta}M_{\leq \theta, \delta}x}})$

One can also get estimates of the norms with multiplicative error $\eta$ by increasing the running time by a factor $1/\eta$.

For a symmetric matrix $M \in \mathbb{R}^{d\times d}$ with spectral norm $|M|=1$ for which we have quantum access, the running time of these algorithms depends on the condition number $\kappa(M)$ of the matrix, that can be replaced by $\kappa_\tau(M)$, a condition threshold where we keep only the singular values bigger than $\tau$, and the parameter $\mu(M)$, a matrix dependent parameter defined in definition \@ref(def:mu). The running time also depends logarithmically on the relative error $\epsilon$ of the final outcome state. Recall that these linear algebra procedures above can also be applied to any rectangular matrix $V \in \mathbb{R}^{n \times d}$ by considering instead the symmetric matrix

$$ \overline{V} = \left ( \begin{matrix} 0 &V \ V^{T} &0 \ \end{matrix} \right ).$$

Linear combination of unitaries, normal forms, and singular value transformations {#subsec:svt}

We continue our journey in quantum linear algebra by discussing the state-of-the-art technique beneath quantum linear algebra, called singular value transformation.

The research of quantum algorithms for machine learning has always used techniques developed in other areas of quantum algorithms. Among the many, we cite quantum algorithms for Hamiltonian simulation and quantum random walks. In fact, using quantum random walks, it is possible to decrease the dependence on the error parameter, from polynomial to $\text{polylog}(1/\epsilon)$ [@childs2012hamiltonian]. Stemming from the research in Hamiltonian simulation [@berry2015hamiltonian], [@low2019hamiltonian], [@berry2015simulating], [@low2017hamiltonian],[@subramanian2019implementing], these techniques have been further optimized, pushing them to the limit of almost optimal time and query complexity. Significant progress in the direction of quantum algorithms for linear algebra was the so-called LCU, or linear combination of unitaries [@childs2012hamiltonian], which again was developed in the context of the Hamiltonian simulation problem.

Let $M = \sum_{i} \alpha_i U_i$ be a linear combination of unitaries $U_i$ with $\alpha_i >0$ for all $i$. Let $V$ be any operator that satisfies  $V|0^m\> := \frac{1}{\sqrt{\alpha}}\sum_i \sqrt{\alpha_i}|i\>$, where $\alpha := \sum_i \alpha_i$.
Then $W := V^{\dagger}UV$ satisfies
\begin{equation}
W\ket{0^{\otimes m}}\ket{\psi} =\frac{1}{\alpha}\ket{0^{\otimes m}}M\ket{\psi} + \ket{\Psi^\perp}
\end{equation}
for all states $\ket{\psi}$, where $U := \sum_i \ket{i}\bra{i} \otimes U_i$ and $(\ket{0^{\otimes m}}\bra{0^{\otimes m}} \otimes I)\ket{\Psi^\perp}=0$.

In recent years a new framework for performing operations on matrices with a quantum computer was developed, which can be found in works [@CGJ18], [@gilyen2019quantum]. We now briefly go through the machinery behind these results, as it will be used throughout this thesis.

Let $A\in \mathbb{C}^{2^s \times 2^s}$. We say that a unitary $U \in \mathbb{C}^{(s+a)\times(s+a)}$ is a ($\alpha, a, \epsilon)$ block encoding of $A$ if:
$$\norm{A - \alpha (\bra{0}^a \otimes I )U( \ket{0}^a \otimes I)  } \leq \epsilon$$ 

We will see that having quantum access to a matrix $A\in\mathbb{C}^{2^w \times 2^w}$, as described in the setting of theorem \@ref(qram), it is possible to implement a $(\mu(A), w+2, \text{polylog}(\epsilon))$ block-encoding of $A$ \footnote{This $\text{polylog}(\epsilon)$ in the block encoding is due to approximation error that one commits when creating quantum access to the classical data structures, i.e. is the approximation that derives from truncating a number $n \in \mathbb{R}$ (which rerepsent an entry of the matrix) up to a certain precision $\epsilon$ Lemma 25 of [@CGJ18].}. Given matrix $U$ which is a $(\alpha, a, \delta)$ block encoding of $A$, and a matrix $V$ which is a $(\beta, b, \epsilon)$ block encoding of $B$, it is simple to obtain a $(\alpha\beta, a+b, \alpha\epsilon+\beta\delta)$ block encoding of $AB$.

For practical purposes, having a block encoding of a matrix $A$, allows one to manipulate its spectra using polynomial approximation of analytic functions. In the following theorem, the notation $P{\Re}(A)$ means that we apply the polynomial $P$ to the singular values of the matrix $A$, i.e. $P{\Re}(A) = \sum_i^r P(\sigma_i)u_iv_i^T$.

Suppose that $U$ is an $(\alpha,a,\epsilon)$-block encoding of the Hermitian matrix $A$. If $\delta\geq 0$ and $P_{\Re}\in\mathbb{R}[x]$ is a degree-$d$ polynomial satisfying that:

-  for all $x\in[-1,1]$, $| P_{\Re}(x)|\leq \frac{1}{2}$.

Then there is a quantum circuit $\tilde{U}$, which is an $(1,a+2,4d\sqrt{\epsilon/\alpha}+\delta)$-encoding of  $P_{\mathcal{R}}(A/\alpha)$, and consists of $d$ applications of $U$ and $U^\dagger$ gates, a single application of controlled-$U$ and $O((a+1)d)$ other one- and two-qubit gates. Moreover we can compute a description of such a circuit with a classical computer in time $O(\text{poly}d,\log(1/\delta))$.

For instance, matrix inversion can be seen as the problem of implementing the singular value transformation of $x \mapsto 1/x$. For this, one needs to get a polynomial approximation of the function $1/x$. While this might seem a simple task, there are small complications. First, one usually does not consider the whole interval $[-1, 1]$. In practice, one excludes the subset of the domain where the function has singularities (i.e. for $1/x$ is around zero). Then, it is preferable to pick a polynomial of a small degree (and small coefficients), as the depth of the circuit depends linearly on the degree of the polynomial.

Given a $(\alpha, a, \epsilon)$-block encoding for a matrix $A$ and a quantum state $\ket{b}$, we can obtain a good approximation of $A\ket{b}/\norm{Ab}$ by first creating the state $\ket{0^a,b}$ and then applying the block encoding of $A$ to it. Then, we can amplify the part of the subspace associated with the state $\ket{0}^{\otimes a}A\ket{b}$. Differently, one might use advanced amplification techniques and reach a similar result. This concept is detailed in the following lemma.

Fix any $\varepsilon \in (0,1/2)$. Let $A \in \mathbb{C}^{N \times N}$ such that $\norm{A}\leq 1$ and $\ket{b}$ a normalized vector in $\mathbb{C}^N$, such that $\norm{A\ket{b}} \geq \gamma$. Suppose that $\ket{b}$ can be generated in complexity $T_b$ and there is a $(\alpha, a, \epsilon)$-block encoding of $A$ for some $\alpha \geq 1$, with $\epsilon \leq \varepsilon\gamma/2$, that can be implemented in cost $T_A$. Then there is a quantum algorithm with complexity
$$O\left(min(\frac{\alpha(T_A + T_b)}{\gamma}, \frac{\alpha T_A\log(1/\epsilon)+T_B}{\gamma})\right) $$
that terminates with success probability at least $2/3$, and upon success generates the state $A\ket{b}/\norm{A\ket{b}}$ to precision $\varepsilon$.

For sake of completeness, we briefly discuss how to prove the first upper bound. Generating $\ket{b}$ and applying the block encoding of $A$ to it, we create a state that is $(\epsilon/\alpha)$-close to: $$\ket{0}^{\otimes a}(\frac{1}{\alpha}A\ket{b}) + \ket{0^\perp} $$ From the hypothesis, we know that $\norm{\frac{1}{\alpha}A\ket{b} } \geq \gamma/\alpha$. We can use $O(\alpha/\gamma)$ calls to amplitude amplification on the initial register being $\ket{0}^{\otimes a}$, to get $\frac{\epsilon}{\gamma}$ close to $\ket{0}^{\otimes a}\frac{A\ket{b}}{\norm{A}\ket{b}}$. The second upper bound is shown by other techniques based on amplitude amplification of singular values of block encoded matrices (i.e. \cite[lemma 47]{CGJ18}, \cite[theorem 2,8]{low2017hamiltonian}).

Regarding the usage of block-encodings for solving with a quantum computer a linear system of equations (i.e. multiplying a quantum state by the inverse of a matrix, and creating a state $\ket{x}$ proportional to $A^{-1}\ket{b}$) we can proceed in an analogous way. First, we need to create block encoding access to $A^{-1}$. Using the following lemma, (where they denoted with $\kappa$ the condition number of $A$) we can implement negative powers of Hermitian matrices.

Let $c \in (0,\infty), \kappa \geq 2$, and let $A$ be an Hermitian matrix such that $I/\kappa \leq A \leq I$. Suppose that $\delta = o(\epsilon/( \kappa^{1+c}(1+c) \log^3\frac{k^{1+c}}{\epsilon}))$ and $U$ is an $(\alpha,a,\delta)$-block encoding of $A$ that can be implemented using $T_U$ gates. Then, for any $\epsilon$, we can implement a unitary $\tilde{U}$ that is a $(2\kappa^c, a, \epsilon)$-block encoding of $H^{-c}$ in cost:
    $$O\left(\alpha \kappa(a+T_U)(1+c)\log^2(\frac{k^{1+c}}{\epsilon})\right)$$

Nevertheless, the algorithm that emerges by using the previous lemma has a quadratic dependence on $\kappa$. To decrease it to an algorithm linear in $\kappa$ the authors used variable time amplitude amplifications[@ambainis2010variable]. Hence, we can restate the theorem \ref{matrix_algebra}, with the improved runtimes, as follows.

Let $M := \sum_{i} \sigma_iu_iv_i^T \in \mathbb{R}^{d \times d}$ such that $\norm{M}_2 =1$, and a vector $x \in \mathbb{R}^d$ for which we have quantum access in time $T_\chi$. There exist quantum algorithms that with probability at least $1-1/poly(d)$ return

- a state $\ket{z}$ such that $| \ket{z} - \ket{Mx}| \leq \epsilon$ in time $\tilde{O}(\kappa(M)(\mu(M)+T_\chi)\log(1/\epsilon))$
- a state $\ket{z}$ such that $|\ket{z} - \ket{M^{-1}x}| \leq \epsilon$ in time $\tilde{O}(\kappa(M)(\mu(M)+T_\chi)\log(1/\epsilon))$
- a state $\ket{M_{\leq \theta, \delta}^+M_{\leq \theta, \delta}x}$  in time $\tilde{O}(T_\chi \frac{ \mu(M) \norm{x}}{\delta \theta \norm{M^{+}_{\leq \theta, \delta}M_{\leq \theta, \delta}x}})$

One can also get estimates of the norms with multiplicative error $\eta$ by increasing the running time by a factor $1/\eta$.

Another important advantage of the new methods is that it provides easy ways to manipulate sums or products of matrices.

Let $M_1, M_2 \in \mathbb{R}^{d \times d}$ such that $\norm{M_1}_2= \norm{M_2}_2 =1$, $M=M_1M_2$,
     and a vector $x \in \mathbb{R}^d$ for which we have quantum access. There exist quantum algorithms that with probability at least $1-1/poly(d)$ return

- a state $\ket{z}$ such that $| \ket{z} - \ket{Mx}| \leq \epsilon$ in time $\tilde{O}(\kappa(M)(\mu(M_1)+\mu(M_2))\log(1/\epsilon))$
- a state $\ket{z}$ such that $|\ket{z} - \ket{M^{-1}x}| \leq \epsilon$ in time $\tilde{O}(\kappa(M)(\mu(M_1)+\mu(M_2))\log(1/\epsilon))$
-  a state $\ket{M_{\leq \theta, \delta}^+M_{\leq \theta, \delta}x}$  in time $\tilde{O}(\frac{ (\mu(M_1)+\mu(M_2)) \norm{x}}{\delta \theta \norm{M^{+}_{\leq \theta, \delta}M_{\leq \theta, \delta}x}})$

One can also get estimates of the norms with multiplicative error $\eta$ by increasing the running time by a factor $1/\eta$.

More generally, applying a matrix $M$ which is the product of $k$ matrices, i.e. $M=M_1\dots M_k$ will result in a runtime of $\kappa(M)(\sum_i^k \mu(M_i) )\log(1/\epsilon)$ factors in the runtime.

Estimation of distances, inner products, norms, and quadratic forms {#sub:distances}

In this section, we report two lemmas that can be used to estimate the inner products, distances, and quadratic forms between vectors. The lemma \@ref(lem:innerproductestimation) has been developed in the work [@kerenidis2019qmeans]. The lemma \@ref(lem:qsp-l1norm) and the other lemmas for inner product estimation in the query model come from [@hamoudi2020quantum].

Inner products and quadratic forms with KP-trees

We can rephrase this theorem saying that we have quantum access to the matrices, but for simplicity we keep the original formulation.

Assume for a matrix $V \in \mathbb{R}^{n \times d}$ and a matrix $C \in \mathbb{R}^{k \times d}$ that the following unitaries
$\ket{i}\ket{0} \mapsto \ket{i}\ket{v_i}$, and $\ket{j}\ket{0} \mapsto \ket{j}\ket{c_j}$ 
can be performed in time $T$ and the norms of the vectors are known. For any $\Delta > 0$ and $\epsilon>0$, there exists a quantum algorithm that  computes

- $\ket{i}\ket{j}\ket{0}  \mapsto   \ket{i}\ket{j}\ket{\overline{d^2(v_i,c_j)}}$ where $|\overline{d^{2}(v_i,c_j)}-d^{2}(v_i,c_j)| \leqslant  \epsilon$ w.p. $\geq 1-2\Delta$
- $\ket{i}\ket{j}\ket{0}  \mapsto   \ket{i}\ket{j}\ket{\overline{(v_i,c_j)}}$ where  $|\overline{(v_i,c_j)}-(v_i,c_j)| \leqslant  \epsilon$ w.p. $\geq  1-2\Delta$

in time $\widetilde{O}\left(\frac{ \norm{v_i}\norm{c_j} T \log(1/\Delta)}{ \epsilon}\right)$.
Let us start by describing a procedure to estimate the square $\ell_2$ distance between the normalized vectors $\ket{v_i}$ and $\ket{c_j}$. We start with the initial state
 $$
 \ket{\phi_{ij}} := \ket{i} \ket{j} \frac{1}{\sqrt{2}}(\ket{0}+ \ket{1})\ket{0}
 $$

 Then, we query the state preparation oracle controlled on the third register to perform the mappings
 $\ket{i}\ket{j}\ket{0}\ket{0} \mapsto \ket{i}\ket{j}\ket{0}\ket{v_i}$ and $\ket{i}\ket{j}\ket{1}\ket{0} \mapsto \ket{i}\ket{j}\ket{1}\ket{c_j}$.
 The state after this is given by,
$$
 \frac{1}{\sqrt{2}}\left( \ket{i}\ket{j}\ket{0}\ket{v_i} + \ket{i}\ket{j}\ket{1}\ket{c_j}\right)
$$
Finally, we apply an Hadamard gate on the the third register to obtain,
$$\ket{i}\ket{j}\left( \frac{1}{2}\ket{0}\left(\ket{v_i} + \ket{c_j}\right) + \frac{1}{2}\ket{1}\left(\ket{v_i} -\ket{c_j}\right)\right)$$
The probability of obtaining $\ket{1}$ when the third register is measured is,
$$ p_{ij} =  \frac{1}{4}(2 - 2\braket{v_i}{c_j}) =  \frac{1}{4} d^2(\ket{v_i}, \ket{c_j}) =  \frac{1 - \langle v_i | c_j\rangle}{2}$$
which is proportional to the square distance between the two normalized vectors.

We can rewrite $\ket{1}\left(\ket{v_i} - \ket{c_j}\right)$ as $\ket{y_{ij},1}$ (by swapping the registers), and hence we have the final mapping
\begin{equation}
 A: \ket{i}\ket{j} \ket{0} \mapsto \ket{i}\ket{j}(\sqrt{p_{ij}}\ket{y_{ij},1}+\sqrt{1-p_{ij}}\ket{G_{ij},0})
(\#eq:QDE)
\end{equation}

 where the probability $p_{ij}$ is proportional to the square distance between the normalized vectors and $G_{ij}$ is a garbage state. Note that the running time of $A$ is $T_A=\tilde{O}(T)$.

Now that we know how to apply the transformation described in Equation \@ref(eq:QDE), we can use known techniques to conclude our subroutine to perform the distance estimation within additive error $\epsilon$ with high probability. The method uses two tools, amplitude estimation, and the median evaluation lemma \@ref(lem:median) from [@wiebe2018quantum], which is a quantum version of the well-known powering-lemma \@ref(lem:powering-lemma).

First, using amplitude estimation (theorem \@ref(thm:thm-ampest-orig)) with the unitary $A$ defined in Equation \ref{QDE}, we can create a unitary operation that maps
$$
\mathcal{U}: \ket{i}\ket{j}  \ket{0} \mapsto \ket{i}\ket{j} \left( \sqrt{\alpha}  \ket{ \overline{p_{ij}}, G, 1} + \sqrt{ (1-\alpha ) }\ket{G', 0}  \right)
$$
 where $G, G'$ are garbage registers, $|\overline{p_{ij}} - p_{ij}  |  \leq \epsilon$ and $\alpha \geq 8/\pi^2$.
 The unitary $\mathcal{U}$ requires $P$ iterations of $A$ with $P=O(1/\epsilon)$. Amplitude estimation thus takes time $T_{\mathcal{U}} = \widetilde{O}(T/\epsilon)$. We can now apply theorem \@ref(lem:median) for the unitary $\mathcal{U}$ to obtain a quantum state $\ket{\Psi_{ij}}$ such that,

$$\|\ket{\Psi_{ij}}-\ket{0}^{\otimes L}\ket{\overline{p_{ij}}, G}\|_2\le \sqrt{2\Delta}$$

The running time of the procedure is $O( T_{\mathcal{U}} \ln(1/\Delta)) = \widetilde{O}( \frac{T }{\epsilon}\log (1/\Delta)  )$.

Note that we can easily multiply the value $\overline{p_{ij}}$ by 4 in order to have the estimator of the square distance of the normalized vectors or compute $1-2\overline{p_{ij}}$ for the normalized inner product. Last, the garbage state does not cause any problem in calculating the minimum in the next step, after which this step is uncomputed.
The running time of the procedure is thus
$O( T_{\mathcal{U}} \ln(1/\Delta)) = O( \frac{T }{\epsilon}\log (1/\Delta)  )$.
The last step is to show how to estimate the square distance or the inner product of the unnormalized vectors. Since we know the norms of the vectors, we can simply multiply the estimator of the normalized inner product with the product of the two norms to get an estimate for the inner product of the unnormalized vectors and a similar calculation works for the distance. Note that the absolute error $\epsilon$ now becomes $\epsilon \norm{v_i}\norm{c_j}$ and hence if we want to have in the end an absolute error $\epsilon$ this will incur a factor of $\norm{v_i}\norm{c_j}$ in the running time. This concludes the proof of the lemma.

It is relatively simple to extend the previous algorithm to one that computes an estimate of a quadratic form. We will consider the case where we have quantum access to a matrix $A$ and compute the quadratic forms $v^TAv$ and $v^TA^{-1}v$. The extension to the case when we have two different vectors, i.e. $v^TAu$ and $v^TA^{-1}u$ is trivial.

Assume to have quantum access to a symmetric positive definite matrix $A \in \mathbb{R}^{n \times n}$ such that $\norm{A}\leq 1$, and to a matrix $V \in \mathbb{R}^{n \times d}$. For $\epsilon > 0$, there is a quantum algorithm that performs the mapping $\ket{i}\ket{0} \mapsto \ket{i}\ket{\overline{s_i}}$, for $|s_i - \overline{s_i}| \leq \epsilon$, where $s_i$ is either:

- $(\ket{v_i},A\ket{v_i})$ in time $O(\frac{\mu(A)}{\epsilon})$
-  $(\ket{v_i},A^{-1}\ket{v_i})$ in time $O(\frac{\mu(A)\kappa(A)}{\epsilon})$

The algorithm can return an estimate of $\overline{(v_i, Av_i)}$ such that $\overline{(v_i, Av_i)} - (v_i, Av_i) \leq \epsilon$ using quantum access to the norm of the rows of $V$ by increasing the runtime by a factor of $\norm{v_i}^2$.
We analyze first the case where we want to compute the quadratic form with $A$, and after the case for $A^{-1}$. Recall that the matrix $A$ can be decomposed in an orthonormal basis $\ket{u_i}$. We can use theorem \ref{th:qla} to perform the following mapping:

\begin{align}
    \ket{i}\ket{v_i}\ket{0} = \ket{i}\frac{1}{N_i}\sum_j^n \alpha_{ij}\ket{u_j}\ket{0} \mapsto \ket{i}\frac{1}{N_i} \sum_i^n \Big(\lambda_i\alpha_{ij}\ket{u_i,0}+ \sqrt{1-\gamma^2}\ket{G,1} \Big) =\\
    \ket{i} \Big(\norm{Av_i}\ket{Av_i,0}+\sqrt{1-\gamma^2}\ket{G,1} \Big)
    =\ket{i}\ket{\psi_i},
\end{align}

where $N_i = \sqrt{\sum_j^n \alpha_{ij}^2}$.
We define $\ket{\phi_i} = \ket{v_i,0}$. Using controlled operations, we can then create the state:

\begin{equation}\label{eq:quadatic A}
\frac{1}{2}\ket{i}\left(\ket{0}(\ket{\phi_i}+\ket{\psi_i}) + \ket{1}(\ket{\phi_i}-\ket{\psi_i})   \right)
\end{equation}

It is simple to check that, for a given register $\ket{i}$, the probability of measuring $0$ is:
$$p_i(0) = \frac{1+\norm{Av_i}\braket{Av_i|v_i}}{2}$$

We analyze the case where we want to compute the quadratic form for $A^{-1}$. For a $C = O(1/\kappa(A))$, we create instead the state:
\begin{align}\label{eq:quadatic A minus 1}
\ket{i}\frac{1}{\sqrt{\sum_i^n \alpha_i^2}} \sum_i^n \Big(\frac{C}{\lambda_i}\alpha_i\ket{v_i,0} + \sqrt{1-\gamma^2}\ket{G,1} \Big) = \ket{i}\ket{\psi_i}
\end{align}

\begin{equation}
U_2 \ket{i}\ket{0} \mapsto \frac{1}{2}\ket{i} \left(\sqrt{\alpha}\ket{p_i(0),y_i,0} + \sqrt{1-\alpha}\ket{G'_i,1} \right)
\end{equation}

and estimate $p_i(0)$ such that $|p_i(0) - \overline{p_i(0)}| < \epsilon$ for the case of $v_i^TAv_i$ and we choose a precision $\epsilon/C$ for the case of $v_i^TA^{-1}v_i$ to get the same accuracy. Amplitude estimation theorem, i.e. theorem \ref{thm:ampest_orig} fails with probability $\leq \frac{8}{\pi^2}$. The runtime of this procedure is given by combining the runtime of creating the state $\ket{\psi_i}$, amplitude estimation, and the median lemma. Since the error in the matrix multiplication step is negligible, and assuming quantum access to the vectors is polylogarithmic, the final runtime is $O(\log(1/\delta)\mu(A)\log(1/\epsilon_2) / \epsilon)$, with an additional factor $\kappa(A)$ for the case of the quadratic form of $A^{-1}$.

Note that if we want to estimate a quadratic form of two unnormalized vectors, we can just multiply this result by their norms. Note also that the absolute error $\epsilon$ now becomes relative w.r.t the norms, i.e. $\epsilon \norm{v_i}^2$.  If we want to obtain an absolute error $\epsilon'$, as in the case with normalized unit vectors, we have to run amplitude estimation with precision $\epsilon'=O(\epsilon/\norm{v_i}^2)$.
        To conclude, this subroutine succeeds with probability $1-\gamma$ and requires time $O(\frac{\mu(A) \log (1/\gamma) \log (1/\epsilon_?)}{\epsilon_1})$, with an additional factor of $\kappa(A)$ if we were to consider the quadratic form for $A^{-1}$, and an additional factor of $\norm{v_i}^2$ if we were to consider the non-normalized vectors $v_i$. This concludes the proof of the lemma.

Note that this algorithm can be extended by using another index register to query for other vectors from another matrix $W$, for which we have quantum access. This extends the capabilities to estimating inner products in the form $\ket{i}\ket{j}\ket{w_i^TA v_i}$.

Inner product and l1-norm estimation with query access

Let $\eta >0$. Given a non-zero vector $u \in [0,1]^N$, with $\max_j u_j = 1$. Given quantum access to $u$ via the operation $\ket j \ket{\bar 0} \to \ket j \ket{ u_j}$ on $O{\log N + \log 1/ \eta}$ qubits, where $u_j$ is encoded to additive accuracy $\eta$. Then:

- There exists a unitary operator that prepares the state $\frac{1}{\sqrt{N}}  \sum_{j=1}^N \ket j  \left( \sqrt{ u_j } \ket{0} + \sqrt{1- u_j} \ket{1} \right)$ with two queries and number of gates $O{\log N + \log 1/\eta}$. Denote this unitary by $U_\chi$.
- Let $\epsilon >0$ such that $\eta \leq \epsilon/ (2N)$ and $\delta \in (0,1)$. There exists a quantum algorithm that  provides an estimate $\Gamma_u$ of the $\ell_1$-norm $\Vert u \Vert_1$  such that $\left \vert \Vert u \Vert_1 - \Gamma_u\right \vert \leq \epsilon \Vert u \Vert_1$, with probability at least $1-\delta$. The algorithm requires $O{\frac{\sqrt{ N}}{\epsilon} \log(1/\delta)}$  queries and $\widetilde{O}{\frac{\sqrt{ N }}{\epsilon} \log\left (1/\delta\right)}$ gates.
- Let  $\xi \in (0,1]$ such that $\eta \leq \xi /4N$ and $\delta \in(0,1)$. An approximation $\ket{ \tilde p} =  \sum_{j=1}^N   \sqrt{ \tilde p_j }\ket j$ to the state $\ket{u} := \sum_{j=1}^N   \sqrt{ \frac{u_j}{\Vert u \Vert_1}}\ket j$ can be prepared with probability $1-\delta$, using $O{\sqrt{N} \log (1/\delta)}$ calls to the unitary of (i) and $\widetilde{O}{\sqrt{N} \log (1/\xi)\log \left (1/\delta \right)}$  gates. The approximation in $\ell_1$-norm of the probabilities is $\left \Vert   \tilde p -  \frac{u}{\Vert u\Vert_1} \right\Vert_1 \leq \xi$.
For the first point,  prepare a uniform superposition of all $\ket j$ with $O(\log N)$ Hadamard gates. With the quantum query access, perform
$$\frac{1}{\sqrt{N}} \sum_{j=1}^N \ket {j} \ket {\bar 0} \to \frac{1}{\sqrt{N}}  \sum_{j=1}^N \ket j  \ket{ u_j} \ket { 0}$$
 $$\to \frac{1}{\sqrt{N}}  \sum_{j=1}^N \ket j  \ket{ u_j}  \left( \sqrt{ u_j} \ket{0} + \sqrt{1-u_j } \ket{1} \right).$$

 The steps consist of an oracle query and a controlled rotation. The rotation is well-defined as $u_j \leq 1$ and costs $O{ \log 1/\eta}$ gates. Then uncompute the data register $\ket{  u_j } $ with another oracle query.

For part 2, define a unitary $\mathcal U = U_\chi \left(\mathbb 1 - 2 \ket{\bar 0}\bra{\bar 0}\right) \left(U_\chi\right)^\dagger$, with $U_\chi$ from (i). Define another unitary by $\mathcal V = \mathbb 1-2 \mathbb 1 \otimes \ket{0} \bra{0}$.
 Using $K$ applications of $\mathcal U$ and $\mathcal V$, Amplitude Estimation \@ref(thm-ampest-orig) allows to provide an estimate $\tilde a$ of the quantity $a = \frac{\Vert u \Vert_1}{N}$  to accuracy 
$\vert dio \vert$. 
 #$\vert \tilde{a} - a \vert \leq 2 \pi \frac{\sqrt{a(1-a)} }{K} + \frac{\pi^2}{K^2}$.  
Following [@van2020quantum], take $K> \frac{6 \pi }{\epsilon} \sqrt{ N}$, which obtains
  \begin{align}
 \left| \tilde a - a \right|
  &\leq& \frac{\pi}{K}\left( 2\sqrt{a}+ \frac{\pi}{K} \right)
  < \frac{\epsilon}{6 }  \sqrt{ \frac{1}{N }  } \left( 2\sqrt{a}+  \frac{\epsilon }{6}\sqrt{ \frac{1}{N } } \right) \nonumber \\
  &\leq&  \frac{\epsilon}{6 }  \sqrt{ \frac{1}{N}  }  \left( 3 \sqrt{a} \right)
  = \frac{\epsilon \sqrt{\Vert u \Vert_1} }{2 N}.
 \end{align}
Since $\Vert u \Vert_1 \geq 1$ by assumption, we have $\left| \tilde{a} - a \right| \leq \frac{\epsilon \Vert u \Vert_1 }{2 N}$.

Also, there is an inaccuracy arising from the additive error $\eta$ of each $u_j$. As it was assumed that
 $\eta\leq \epsilon / (2N)$,  the overall multiplicative error $\epsilon$ is obtained for the estimation.
 For performing a single run of amplitude estimation with $K$ steps,
 we require
 $O{K} =O{\frac{\sqrt{ N }}{\epsilon} }$
 queries to the oracles and
 $O\left(\frac{\sqrt{ N }}{\epsilon} \left(\log N + \log (N / \epsilon)  \right) \right)$
 gates.

  For part 3, rewrite the state from part 1
 as
 \begin{align} 
 \sqrt{ \frac{{\Vert  u \Vert_1} }{N}}  \sum_{j=1}^N&    \sqrt{ \frac{u_j  }{{\Vert  u \Vert_1}}} \ket j \ket{0}  +  \sqrt{1-\frac{{\Vert  u \Vert_1}}{N }}  \sum_{j=1}^N  \sqrt{\frac{1- u_j }{N -{\Vert  u \Vert_1}} } \ket j \ket{1}.\nonumber
 \end{align}
 Now amplify the $\ket 0$ part using Amplitude Amplification [@brassard2002quantum] via the exponential search technique without knowledge of the normalization, to prepare
 $\sum_{j=1}^N \ket j   \sqrt{ \frac{u_j}{\Vert u \Vert_1}}$ with success probability $1-\delta$.
 The amplification requires $O{\sqrt{ \frac{N }{ \Vert u \Vert_1}}\log (1/\delta)}= O{\sqrt N \log (1/\delta)}$ calls to the unitary of part 1, as ${\Vert u \Vert_1} \geq 1$. The gate complexity derives from the gate complexity of part 1.

Denote the  $\eta$-additive approximation to $u_j$ by $\tilde u_j$,
and evaluate the $\ell_1$-distance of the probabilities.
 First, $\left \vert \Vert u\Vert_1 - \Vert \tilde u\Vert_1\right \vert \leq N \eta$.
 One obtains $\left \Vert   \tilde p -  \frac{u}{\Vert u\Vert_1} \right \Vert_1 =\left \Vert  \frac{\tilde u}{{\Vert \tilde u\Vert_1}}  -  \frac{u}{\Vert u\Vert_1} \right \Vert_1 \leq \sum_j \left \vert \frac{\tilde u_j}{{\Vert \tilde  u\Vert_1}}  -  \frac{u_j}{{\Vert \tilde u\Vert_1}} \right \vert + \sum_j \left \vert \frac{ u_j}{{\Vert \tilde u\Vert_1}}  -  \frac{u_j}{\Vert u\Vert_1}\right \vert  \leq \frac{N \eta} {{\Vert \tilde u\Vert_1}} + \frac{ N \eta } {{\Vert \tilde u\Vert_1}}$. We also obtain $\frac{1}{ {\Vert \tilde u\Vert_1} } \leq \frac{1}{ \Vert u\Vert_1 -N\eta } \leq \frac{2}{ \Vert u\Vert_1}$ for $\eta \leq  \Vert u\Vert_1 / 2 N$. Since $\eta \leq \Vert u\Vert_1 \xi/(4N)$, the distance is $\left \Vert   \tilde p -  \frac{u}{\Vert u\Vert_1} \right \Vert_1 \leq \xi$ as desired.
Let $\epsilon,\delta \in(0,1)$.
Given quantum access to two vectors $u,v \in [0,1]^N$, where $u_j$ and $v_j$ are encoded to additive accuracy $\eta= O{1/N}$. Then, an estimate $I$ for the inner product can be provided such that $\vert I - u\cdot v /\Vert u\Vert_1 \vert \leq \epsilon\  u\cdot v /\Vert u\Vert_1$ with success probability $1-\delta$.
This estimate is obtained with $O{\frac{ \sqrt{N} }{\epsilon} \log \left (\frac{1}{\delta} \right )  }$ queries and $\widetilde{O}{\frac{ \sqrt{N} }{\epsilon} \log \left (\frac{1}{\delta} \right )  }$ quantum gates.
Via Lemma \@ref(lem:find-minimum-orig}, determine $u_{\max}$ with success probability $1-\delta$ with $O{\sqrt N \log \frac{1}{\delta}}$ queries and $\widetilde{O}{\sqrt N \log \left( \frac{1}{\delta}\right )}$ quantum gates.

Apply  Lemma \@ref(lem:unitaryU) with the vector $\frac{ u}{ u_{\max}}$ to obtain an estimate $\Gamma_u$ of the norm $\left \Vert  \frac{ u}{ u_{\max}} \right \Vert_1$ to relative accuracy $\epsilon_u= \epsilon/2$ with success probability $1-\delta$.

This estimation takes $O{\frac{ \sqrt{N} }{\epsilon} \log \left (\frac{1}{\delta} \right )  }$ queries and $\widetilde{O}{\frac{ \sqrt{N} }{\epsilon} \log \left (\frac{1}{\delta} \right )  }$ quantum gates.

 Define the vector $z$ with $z_j = u_j v_j$.
Via Lemma \@ref(lem:find-minimum-orig), determine $z_{\max}$ with success probability $1-\delta$ with $O{\sqrt N \log \frac{1}{\delta}}$ queries and $\widetilde{O}{\sqrt N \log \left( \frac{1}{\delta}\right )}$ quantum gates.
 If $z_{\max} = 0$ up to numerical accuracy, the estimate is $I = 0$ and we are done.
 Otherwise,
 apply  Lemma \@ref(lem:qsp-l1norm) with the vector $\frac{ z}{ z_{\max}}$ to obtain an estimate $\Gamma_z$ of the norm $\left \Vert  \frac{ z}{ z_{\max}} \right \Vert_1$ to relative accuracy $\epsilon_z = \epsilon/2$ with success probability $1-\delta$.
 This estimation takes $O{\frac{ \sqrt{N} }{\epsilon} \log \left (\frac{1}{\delta} \right )  }$ queries and $\widetilde{O}{\frac{ \sqrt{N} }{\epsilon} \log \left (\frac{1}{\delta} \right )  }$ quantum gates.

With Lemma \@ref(lem:ratio-relative-general), we have
 \begin{align}
 \left \vert \frac{\Gamma_z}{\Gamma_u} - \frac{u_{\max}}{z_{\max}}\frac{u\cdot v}{\Vert u\Vert_1} \right \vert &\leq& \frac{u_{\max}}{z_{\max}} \frac{u\cdot v }{\Vert u\Vert_1 } \frac{\epsilon_z + \epsilon_u}{ (1-\epsilon_u)} \\
 &\leq& 2\epsilon \frac{u_{\max}}{z_{\max}} \frac{u\cdot v }{\Vert u\Vert_1 },
 \end{align}
 since $\epsilon_u < 1/2$.
 Set
 \begin{align}
 I= \frac{z_{\max}}{u_{\max}} \frac{\Gamma_z}{\Gamma_u},
 \end{align}
 and we have $\vert I - u\cdot v /\Vert u\Vert_1 \vert \leq 2\epsilon\  u\cdot v /\Vert u\Vert_1$.
The total success probability of  the four probabilistic steps is at least $1-4\delta$ via a union bound (theorem \@ref(thm:unionbound)). Choosing $\epsilon \to \epsilon/2$ and $\delta \to \delta/4$ leads to the result.
 Let $\epsilon,\delta \in(0,1)$.
 Given quantum access to a non-zero vector $u \in [0,1]^N$ and another vector $v \in [-1,1]^N$, where $u_j$ and $v_j$ are encoded to additive accuracy $\eta= O{1/N}$. Then,
 an estimate $I$ for the inner product can be provided such that $\vert I - u\cdot v / \Vert u\Vert_1 \vert \leq \epsilon$ with success probability $1-\delta$.
 This estimate is obtained with $O{\frac{ \sqrt{N} }{\epsilon} \log \left (\frac{1}{\delta} \right )  }$ queries and $\widetilde{O}{\frac{ \sqrt{N} }{\epsilon} \log \left (\frac{1}{\delta} \right )  }$ quantum gates.

Note that as a byproduct, the value $u{\max}$ and an estimate of $\Vert u /u{\max} \Vert_1$ with relative accuracy $\epsilon$ can be provided with probability at least $1-\delta$.

Via Lemma \@ref(lem:find-minimum-orig), determine $\Vert u\Vert_{\max}$ with success probability $1-\delta$ with $O{\sqrt N \log \frac{1}{\delta}}$ queries and $\widetilde{O}{\sqrt N  \log \left( \frac{1}{ \eta}\right) \log \left( \frac{1}{\delta}\right )}$ quantum gates.
Apply  Lemma \@ref(lem:qsp-l1norm) with the vector $\frac{ u}{ u_{\max}}$ to obtain an estimate $\Gamma_u$ of the norm $\left \Vert  \frac{ u}{ u_{\max}} \right \Vert_1$ to relative accuracy $\epsilon_u= \epsilon/2$ with success probability $1-\delta$.

This estimation takes $O{\frac{ \sqrt{N} }{\epsilon} \log \left (\frac{1}{\delta} \right )  }$ queries and $\widetilde{O}{\frac{ \sqrt{N} }{\epsilon} \log \left (\frac{1}{\delta} \right )  }$ quantum gates.

Similarily, consider the vector $z$ with elements $z_j := u_j \left (v_j+3\right) \in [0,4]$.
Determine $\Vert z\Vert_{\max}$ with success probability $1-\delta$ with $O{\sqrt N \log \frac{1}{\delta}}$ queries and $\widetilde{O}{\sqrt N  \log \left( \frac{1}{\delta}\right )}$ quantum gates.
Apply  Lemma \@ref(lem:qsp-l1norm) with the vector $z/ z_{\max}$ to obtain an estimate $\Gamma_z$ of the norm $\Vert z/ z_{\max} \Vert_1$ to relative accuracy $\epsilon_z =  \epsilon/2$ with success probability $1-\delta$.

This estimation takes $O{\frac{ \sqrt{N} }{\epsilon} \log \left (\frac{1}{\delta} \right )  }$ queries and $\widetilde{O}{\frac{ \sqrt{N} }{\epsilon} \log \left (\frac{1}{\delta} \right )  }$.

The exact quantities are related via
\begin{align}
\frac{u\cdot v}{\Vert u\Vert_1}  = \frac{z_{\max} }{u_{\max} } \frac{ \Vert \frac{z}{ z_{\max}} \Vert_1 } { \Vert \frac{ u}{ u_{\max}} \Vert_1}  - 3.
\end{align}
 Considering the estimator $I = \frac{z_{\max} }{u_{\max} } \frac{ \Gamma_z } { \Gamma_u}  - 3$, from Lemma \@ref(lem:ratio-relative-general), we have
\begin{align}
\left  \vert I -  \frac{u\cdot v}{ \Vert u\Vert_1 } \right \vert &=& \frac{z_{\max} }{u_{\max} } \left \vert   \frac{ \Gamma_z } { \Gamma_u} - \frac{ \Vert \frac{z}{ z_{\max}} \Vert_1 } { \Vert \frac{ u}{ u_{\max}} \Vert_1}  \right \vert \\ &\leq&
\frac{ \epsilon_u + \epsilon_{z}}{1-  \epsilon_u}  \frac{ \Vert z \Vert_1 } { \Vert u\Vert_1} \leq 8 \epsilon. \nonumber
\end{align}

In the last steps we have used that
\begin{align}
\frac{ \Vert z \Vert_1 } { \Vert u\Vert_1} \equiv \frac{\sum_j u_j  (v_j+3)}{\sum_j u_j } \leq\frac{4 \sum_j  u_j }{\sum_j u_j } = 4,
\end{align}
and $\epsilon_u < 1/2$.
All steps together take $O{\frac{\sqrt N}{\epsilon} \log \frac{1}{\delta}}$ queries and $\widetilde{O}{\frac{\sqrt N}{\epsilon}  \log \left( \frac{1}{\delta}\right )}$ gates.
The total success probability of all the probabilistic steps is at least $1-4\delta$ via a union bound. Choosing $\epsilon \to \epsilon/8$ and $\delta \to \delta/4$ leads to the result.

SVE-based quantum algorithms

In the following section, we will cover some quantum algorithms based on singular value estimation. Some of them are here just because they are simple enough to have a good pedagogical value, while some of them we believe will be really useful in performing data analysis.

Log-determinant

This is not the fastest algorithm for estimating the log-determinant, but it's worth mentioning here because it perhaps the first thing one would try to do in order to estimate this quantity. It also is a good example of the power of quantum singular value estimation, and checking the correctness of this proof might be a good exercise.

knitr::include_graphics("algpseudocode/logdet-sve.png")
Under assumption \ref{assumption}, algorithm \ref{algo:logdet-sve} returns
$\overline{\log\det(A)}$ such that $|\overline{\log\det(A)} - \log\det(A)| < \epsilon |\log\det(A)|$ in time 
$\widetilde{O}(\mu \kappa^3/\epsilon^2).$
We can rewrite the quantum state encoding the representation of $A$ (which we can create with quantum access to $A$) as follow:
\begin{equation}
|A\rangle = \frac{1}{\|A\|_F} \sum_{i,j=1}^n a_{ij}|i,j\rangle = \frac{1}{\|A\|_F} \sum_{j=1}^n \sigma_j |u_j\rangle|u_j\rangle.
\end{equation}
Starting from the state $\ket{A}$, we can apply SVE (see Lemma  \ref{sveplus1}) to $\ket{A}$ up to precision $\epsilon_1$ to obtain
$$\frac{1}{\|A\|_F} \sum_{j=1}^n \sigma_j |u_j\rangle|u_j\rangle |\tilde{\sigma}_j\rangle,$$
where $|\tilde{\sigma}_j-\sigma_j|\leq \epsilon_1$.
Since $\norm{A} \leq 1$, using controlled operations, we can prepare

\begin{align}
\frac{1}{\|A\|_F} \sum_{i=1}^n \sigma_j |u_j\rangle|u_j\rangle
\ket{\tilde{\sigma}_j}
\left(
C\frac{\sqrt{-\log \tilde{\sigma}_j}}{\tilde{\sigma}_j}\ket{0}
+ \ket{0^\bot}
\right),
(\#eq:tracelogdet)
\end{align}

  where $C=\min_j \tilde{\sigma}_j/\sqrt{|\log \tilde{\sigma}_j|} \approx \sigma_{\min}/\sqrt{|\log \sigma_{\min}|}
=1/\kappa\sqrt{\log \kappa}$.
The probability of $\ket{0}$ is
$$P = -\frac{C^2}{\|A\|_F^2} \sum_{j=1}^n  \frac{\sigma_j^2}{\tilde{\sigma}_j^2} \log \tilde{\sigma}_j.$$

First, we do the error analysis.
Note that
\begin{align}
\left| \sum_{j=1}^n  \frac{\sigma_j^2}{\tilde{\sigma}_j^2} \log \tilde{\sigma}_j - \sum_{j=1}^n \log \sigma_j \right|
&\leq& \left|\sum_{j=1}^n \frac{\sigma_j^2}{\tilde{\sigma}_j^2} \log \tilde{\sigma}_j - \sum_{j=1}^n \frac{\sigma_j^2}{\tilde{\sigma}_j^2}\log \sigma_j \right|
+ \left|\sum_{j=1}^n \frac{\sigma_j^2}{\tilde{\sigma}_j^2} \log\sigma_j - \sum_{j=1}^n \log \sigma_j \right| \\
&\leq&
\sum_{j=1}^n \frac{\sigma_j^2}{\tilde{\sigma}_j^2} |\log \tilde{\sigma}_j - \log \sigma_j | +  \sum_{j=1}^n \frac{|\sigma_j^2-\tilde{\sigma}_j^2|}{\tilde{\sigma}_j^2}  |\log \sigma_j |  \\
&\leq& \sum_{j=1}^n (1 + \frac{\epsilon_1}{\tilde{\sigma}_j})^2 (\frac{\epsilon_1}{\tilde{\sigma}_j}+O(\frac{\epsilon_1^2}{\tilde{\sigma}_j^2})) + (2\kappa\epsilon_1 +\kappa^2\epsilon_1^2)
|\log\det(A)| \\
&\leq& n  (\kappa\epsilon_1+O(\kappa^2\epsilon_1^2)) + (2\kappa\epsilon_1 +\kappa^2\epsilon_1^2) |\log \det(A)| \\
&=& (n+2|\log \det(A)|) (\kappa\epsilon_1+O(\kappa^2\epsilon_1^2)).
\end{align}
In the third inequality, we use the result
that $\sigma_j\leq \tilde{\sigma}_j+\epsilon_1$.

Denote $P'$ as the $\epsilon_2$-approximation of $P$ obtained by amplitude estimation, then the above analysis shows that
$-\|A\|_F^2P'/C^2$ is an $(n+2|\log \det(A)|) (\kappa \epsilon_1 + O(\kappa^2 \epsilon_1^2)) +\epsilon_2\|A\|_F^2/C^2$
approximation of $\log\det(A)$. Note that

\begin{align}
&& (n+2|\log \det(A)|) (\kappa \epsilon_1 +
O(\kappa^2 \epsilon_1^2))
+\epsilon_2\|A\|_F^2/C^2 \\
&=&
(n+2|\log \det(A)|) (\kappa \epsilon_1 +
O(\kappa^2 \epsilon_1^2))
+\epsilon_2 \|A\|_F^2  \kappa^2\log \kappa \\
&\leq&
(n+2n\log \kappa) (\kappa \epsilon_1 +
O(\kappa^2 \epsilon_1^2))
+n\epsilon_2 \kappa^2\log \kappa \\
&=& O(n\epsilon_1\kappa\log \kappa+n\epsilon_2\kappa^2\log \kappa).
\end{align}

To make sure the above error is bounded by $n\epsilon$ it suffcies to choose
$\epsilon_1=\epsilon/\kappa\log \kappa$
and $\epsilon_2=\epsilon/\kappa^2\log \kappa$.

Now we do the runtime analysis. The runtime of the algorithm mainly comes from the using of SVE and the performing of amplitude estimation on the state in  (\@ref(eq:tracelogdet)).
Using quantum singular value estimation, the complexity to obtain the state
\@ref(eq:tracelogdet) is $\widetilde{O}(\mu /\epsilon_1)$.
The complexity to perform amplitude estimation  is $\widetilde{O}(\mu /\epsilon_1\epsilon_2)=\widetilde{O}(\mu \kappa^3(\log \kappa)^2/\epsilon^2)$.

SVE-based linear algebra

Estimation of the spectral norm and the condition number

Explained variance

Singular value estimation of a product of two matrices

This is an example of an algorithm that has been superseded by recent development in singular value transformation. Nevertheless, it is a non-trivial way of using SVE, which a nice mathematical error analysis.

Assume to have quantum access to matrices $P \in \mathbb{R}^{d\times d}$ and $Q \in \mathbb{R}^{d \times d}$. Define $W=PQ = U\Sigma V^T$  and $\epsilon > 0$ an error parameter. There is a quantum algorithm that with probability at least $1-poly(d)$ performs the mapping $\sum_{i}\alpha\ket{v_i} \to \sum_{i}\alpha_i\ket{v_i}\ket{\overline{\sigma_i}}$ where $\overline{\sigma_i}$ is an approximation of the eigenvalues $\sigma_i$ of $W$ such that $|\sigma_i - \overline{\sigma}_i | \leq \epsilon$, in time $\tilde{O}\left(\frac{ ( \kappa(P) + \kappa(Q) ) (\mu(P)+\mu(Q))}{\varepsilon}\right)$.
We start by noting that for each singular value $\sigma_{i}$ of $W$ there is a corresponding eigenvalue  $e^{-i\sigma_i}$ of the unitary matrix $e^{-iW}$. Also, we note that we know how to multiply by $W$ by applying theorem \@ref(matrix_algebra) sequentially with $Q$ and $P$. This will allow us to approximately apply the unitary $U=e^{-iW}$. The last step will consist of the application of phase estimation to estimate the eigenvalues of $U$ and hence the singular values of $W$. Note that we need $W$ to be a symmetric matrix because of the Hamiltonian simulation part. In case $W$ is not symmetric, we redefine it as
$$
W  =
\begin{bmatrix}
    0 & PQ\\
    (PQ)^T & 0
\end{bmatrix}
$$
Note we have $W=M_1M_2$ for the matrices $M_1, M_2$ stored in QRAM and defined as

$$
M_1 = \begin{bmatrix}
    P & 0\\
    0 & Q^T
\end{bmatrix},
M_2 = \begin{bmatrix}
    0 & Q\\
    P^T & 0
\end{bmatrix}.
$$

We now show how to approximately apply $U=e^{-iW}$ efficiently. Note that for a symmetric matrix $W$ we have $W=V\Sigma V^T$ and using the Taylor expansion of the exponential function we have

$$U = e^{-iW} = \sum_{j=0}^{\infty} \frac{(-iW)^j}{j!} =   V \sum_{j=0}^{\infty} \frac{(-i\Sigma)^j}{j!} V^T$$

With $\widetilde{U}$ we denote our first approximation of $U$, where we truncate the sum after $\ell$ terms.

$$\widetilde{U} = \sum_{j=0}^{\ell} \frac{(-iW)^j}{j!} =   V \sum_{j=0}^{\ell} \frac{(-i\Sigma)^j}{j!} V^T$$

We want to chose $\ell$ such that $\norm{U - \widetilde{U}} < \epsilon/4$. We have:

\begin{eqnarray*}
\norm{U - \widetilde{U}} & \leq & || \sum_{j=0}^{\infty} \frac{(-iW)^j}{j!} - \sum_{j=0}^{\ell} \frac{(-iW)^j}{j!}   ||  \leq
|| \sum_{j={\ell+1}}^{\infty} \frac{(-iW)^j}{j!} || \leq \sum_{j={\ell+1}}^{\infty}  || \frac{(-iW)^j}{j!} || \leq \sum_{j={\ell+1}}^{\infty}  \frac{1}{j!} \\
& \leq & \sum_{j={\ell+1}}^{\infty}  \frac{1}{2^{j-1}} \leq 2^{-\ell +1}
\end{eqnarray*}

where we used triangle inequality and that $\norm{W^j}\leq 1$. Choosing $\ell = O(\log 1/ \varepsilon)$ makes the error less than $\epsilon/4$.
%We can approximate a positive series where the term $a_n$ satisfy the following two conditions: $0 \leq a_n \leq Kr^n$ with $K>0, 0<r<1$ by expressing the error as the geometric series $\frac{Kr^{N+1}}{1-r}$. In our case $K=1$ and $r=1/2$. For a given $\epsilon$ we have to find $\ell$ such that $\frac{(\frac{1}{2})^{\ell+1}}{1-(\frac{1}{2})} \leq \epsilon$. By taking $\ell = O(\log 1/\epsilon)$ we can easily satisfy the error guarantee.

In fact, we cannot apply $\widetilde{U}$ exactly but only approximately, since we need to multiply with the matrices $W^j, j\in[\ell]$ and we do so by using the matrix multiplication algorithm for the matrices $M_1$ and $M_2$. For each of these matrices, we use an error of $\frac{\epsilon}{8 \ell}$ which gives an error for $W$ of $\frac{\epsilon}{4 \ell}$ and an error for $W^j$ of at most $\frac{\epsilon}{4}$. The running time for multiplying with each $W^j$ is at most $O(\ell ( \kappa(M_1)\mu(M_1) \log( 8\ell/\epsilon) + \kappa(M_2)\mu(M_2) \log( 8\ell/\epsilon)  ))$ by multiplying sequentially. Hence, we will try to apply the unitary ${U}$ by using the Taylor expansion up to level $\ell$ and approximating each $W^j, j\in [\ell]$ in the sum through our matrix multiplication procedure that gives error at most $\frac{\epsilon}{4}$.

In order to apply $U$ on a state $\ket{x} = \sum_{i} \alpha_i \ket{v_i}$, let's assume $\ell+1$ is a power of two and define $N_l = \sum_{j=0}^l (\frac{(-i)^j}{j!})^2$. We start with the state
$$\frac{1}{\sqrt{N_l}}\sum_{j=0}^l \frac{-i^j}{j!}\ket{j}\ket{x}$$

Controlled on the first register we use our matrix multiplication procedure to multiply with the corresponding power of $W$ and get a state at most $\epsilon/4$ away from the state

%$$\frac{1}{N_l} \sum_{j=0}^l \frac{-i^j}{j!}e^{\theta}\ket{j}\ket{W^jx}$$

$$\frac{1}{\sqrt{N_l}}\sum_{j=0}^l \frac{-i^j}{j!}\ket{j}\ket{W^jx}.$$

We then perform a Hadamard on the first register and get a state  $\epsilon/4$ away from the state

$$\frac{1}{\sqrt{\ell}} \ket{0} \left( \frac{1}{\sqrt{N'}} \sum_{j=0}^l \frac{-i^j}{j!} \ket{W^jx}\right) + \ket{0^\bot} \ket{G}$$

where $N'$ just normalizes the state in the parenthesis. Note that after the Hadamard on the first register, the amplitude corresponding to each $\ket{i}$ is the first register is the same. We use this procedure inside an amplitude amplification procedure to increase the amplitude $1/\sqrt{\ell}$ of $\ket{0}$ to be close to 1, by incurring a factor $\sqrt{\ell}$ in the running time. The outcome will be a state  $\epsilon/4$ away from the state

$$\left( \frac{1}{\sqrt{N'}} \sum_{j=0}^l \frac{-i^j}{j!} \ket{W^jx}\right) = \ket{\tilde{U}x}$$
which is the application of $\widetilde{U}$. Since $\norm{U - \widetilde{U}} \leq \epsilon/4$, we have that the above procedure applies a unitary $\overline{U}$ such that $\norm{U - \overline{U}} \leq \epsilon/2$. Note that the running time of this procedure is given by the amplitude amplification and the time to multiply with $W^j$, hence we have that the running time is

$$O(\ell^{3/2} ( \kappa(M_1)\mu(M_1) \log( 8\ell/\epsilon) + \kappa(M_2)\mu(M_2) \log( 8\ell/\epsilon)  )$$

Now that we know how to apply $\overline{U}$, we can perform phase estimation on it with error $\epsilon/2$. This provides an algorithm for estimating the singular values of $W$ with overall error of $\epsilon$. The final running time is

$$O(\frac{\ell^{3/2}}{\epsilon} ( \kappa(M_1)\mu(M_1) \log( 8\ell/\epsilon) + \kappa(M_2)\mu(M_2) \log( 8\ell/\epsilon)  )$$

We have $\mu(M_1)=\mu(M_2)= \mu(P)+\mu(Q)$ and $\kappa(M_1)=\kappa(M_2) = \frac{max \{ \lambda^{P}_{max}, \lambda^{Q}_{max}  \}}{ min \{ \lambda^{P}_{min}, \lambda^{Q}_{min}  \}} \leq \kappa(P)+\kappa(Q)$, and since $\ell=O(\log 1/\epsilon)$the running time can be simplified to

$$\tilde{O}(\frac{ ( \kappa(P) + \kappa(Q))(\mu(P)+\mu(Q))}{\epsilon} ).$$

Estimating average and variance of a function

Albeit the ideas treated in this post are somehow well-digested in the mind of many quantum algorithms developers, I decided to write this page inspired by [@woerner2019quantum]. Here I want to describe just the main technique employed by their algorithm (namely, how to use amplitude estimation to get useful information out of a function).

Suppose we have a random variable $X$ described by a certain probability distribution over $N$ different outcomes, and a function $f: {0,\cdots N} \to [0,1]$ defined over this distribution. How can we use quantum computers to evaluate some properties of $f$ such as expected value and variance faster than classical computers?

Let's start by translating into the quantum realm these two mathematical objects. The probability distribution is (surprise surprise) represented in our quantum computer by a quantum state over $n=\lceil \log N \rceil$ qubits. $$\ket{\psi} = \sum_{i=0}^{N-1} \sqrt{p_i} \ket{i} $$ where the probability of measuring the state $\ket{i}$ is $p_i,$ for $p_i \in [0, 1]$. Basically, each bases of the Hilbert space represent an outcome of the random variable.

The quantization of the function $f$ is represented by a linear operator $F$ acting on a new ancilla qubit (here on the right) as:

$$ F: \ket{i}\ket{0} \to \ket{i}\left(\sqrt{1-f(i)}\ket{0} + \sqrt{f(i)}\ket{1}\right) $$

If we apply $F$ with $\ket{\psi}$ as input state we get:

$$ \sum_{i=0}^{N-1} \sqrt{1-f(i)}\sqrt{pi}\ket{i}\ket{0} + \sum{i=0}^{N-1} \sqrt{f(i)}\sqrt{p_i}\ket{i}\ket{1} $$

Observe that the probability of measuring $\ket{1}$ in the ancilla qubit is $\sum_{i=0}^{N-1}p_if(i)$, which is $E[f(X)]$. By sampling the ancilla qubit we won't get any speedup compared to a classical randomized algorithm with oracle access to the function, but applying amplitude estimation [@brassard2002quantum %] to the ancilla qubit on the right, we can get an estimate of $E[F(X)]$ with precision $\epsilon$, quadratically faster than a classical computer: in only $O(\frac{1}{\epsilon})$ queries to $f$.

Finally, observe that:

Hamiltonian simulation

These notes based on Childs' Lecture notes, i.e. [@ChildsLectureNotes], Section 5

Introduction to Hamiltonians

The only way possible to start a chapter on Hamiltonian simulation would be to start from the work of Feynman, who had the first intuition on the power of quantum mechanics for simulating physics with computers. We know that the Hamiltonian dynamics of a closed quantum system, weather its evolution changes with time or not is given by the Schrödinger equation:

$$\frac{d}{dt}\ket{\psi(t)} = H(t)\ket{\psi(t)}$$

Given the initial conditions of the system (i.e. $\ket{\psi(0)}$ ) is it possible to know the state of the system at time $t: \ket{\psi(t)} = e^{-i (H_1t/m)}\ket{\psi(0)}$.

As you can imagine, classical computers are supposed to struggle to simulate the process that builds $\ket{\psi(t)}$, since this equation describes the dynamics of any quantum system, and we don’t think classical computers can simulate that efficiently for any general Hamiltonian $H$. But we understood that quantum computers can help to simulate the dynamics of another quantum system.

Why we might want to do that?

An example would be the following. Imagine you are a quantum machine learning scientist, and you have just found a new mapping between an optimization problem and an Hamiltonian dynamics, and you want to use quantum computer to perform the optimization [@otterbach2017unsupervised]. You expect a quantum computers to run the Hamiltonian simulation for you, and then sample useful information from the resulting quantum sate. This result might be fed again into your classical algorithm to perform ML related task, in a virtuous cycle of hybrid quantum-classical computation, which we will discuss more in another chapter.

Another example, perhaps more akin to the original scope of Hamiltonian simulation, is related to quantum chemistry. Imagine that are a chemist, and you have developed a hypothesis for the Hamiltonian dynamics of a chemical compound. Now you want to run some experiments to see if the formula behaves according to the experiments (and you cannot simulate numerically the experiment). Or maybe you are testing the properties of complex compounds you don’t want to synthesize.

We can formulate the problem of Hamiltonian simulation in this way:

Given a state $\ket{\psi(0)}$ and an Hamiltonian $H$, obtain a state $\overline{\ket{\psi(t)}}$ such that $\|\overline{\ket{\psi(t)}}-e^{-iHt}\ket{\psi(0)}\| \leq \epsilon$ in some norm.

(Note that also this problem can be reformulated in the context of density matrices, where usually the trace norm is used as a distance between quantum states).

This leads us to the definition of efficiently simulable Hamiltonian:

Given a state $\ket{\psi(0)}$ and an Hamiltonian $H$ acting on $n$ qubits, we say $H$ can be efficiently simulated if, $\forall t \geq 0, \forall \epsilon \geq 0$ there is a quantum circuit $U$ such that $\| U - e^{-iHt}\| < \epsilon$ using a number of gates that is polynomial in $n,t, 1/\epsilon$.


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Scinawa commented 3 years ago

Closed by Trong!