What steps will reproduce the problem?
1. import markdown2
2. markdown2.markdown(u'[link](http://example.com/тест)')
What is the expected output? What do you see instead?
now this produces following output:
>>> u'<p><a
href="http://example.com/\xd1\x82\xd0\xb5\xd1\x81\xd1\x82">link</a></p>\n'
it would be nice to see more standards compliant
>>> u'<p><a href="http://example.com/%D1%82%D0%B5%D1%81%D1%82">link</a></p>\n'
What version of the product are you using? On what operating system?
1.0.1.15 on ubuntu
Please provide any additional information below.
this can be done quite easily with urllib2.quote
Original issue reported on code.google.com by atregoub...@gmail.com on 8 Oct 2009 at 9:52
Original issue reported on code.google.com by
atregoub...@gmail.com
on 8 Oct 2009 at 9:52