Closed ppreshant closed 2 years ago
Fixed with 40b46ed3ba7078b3cad319f35e616a4619ea9e18 ; 539224f092e24787cc41d4e85c72d07044cc43ca
LOD copies/ul RNA = LOD|droplet / [0.86 nl/droplet x n total droplets x 10/22 fraction of template within droplet] = LOD|droplet / 1e-3 ul/nl x (0.39091 x n)
Briefly the final formula are :
LOD_droplets = 3 + max(negative_controls$PositiveDroplets)
avg_inverse_total_droplet_count <- mean(1/fl$AcceptedDroplets)
LOD = LOD_droplets * 2558.14 * avg_inverse_total_droplet_count # see the LOD googledoc for details
DZ's LOD calculations in the function append_LOD_info() is taking the wells with 3 droplets treating their copies/ul avg number as the LOD. Is there a better way to calculating this?
code used for the calculation shown here
Here's the summary of LOD method after discussing with Adam Brown and Zach - LOD LOQ detailed calculations