the output equation of a linearSysDT is y[i] = Cx[i] + Du[i], i.e., the indices of x and u are the same
The current implementation of @linearSysDT/reach.m in line 66, however, results in y[i-1] = Cx[i] + Du[i-1], i.e., the indices of x and u are different.
the output equation of a linearSysDT is y[i] = Cx[i] + Du[i], i.e., the indices of x and u are the same
The current implementation of @linearSysDT/reach.m in line 66, however, results in y[i-1] = Cx[i] + Du[i-1], i.e., the indices of x and u are different.