Tcdian / keep

今天不想做,所以才去做。
MIT License
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100. Same Tree #256

Open Tcdian opened 4 years ago

Tcdian commented 4 years ago

100. Same Tree

给定两个二叉树,编写一个函数来检验它们是否相同。

如果两个树在结构上相同,并且节点具有相同的值,则认为它们是相同的。

Example 1

Input:     1         1
          / \       / \
         2   3     2   3

        [1,2,3],   [1,2,3]

Output: true

Example 2

Input:     1         1
          /           \
         2             2

        [1,2],     [1,null,2]

Output: false

Example 3

Input:     1         1
          / \       / \
         2   1     1   2

        [1,2,1],   [1,1,2]

Output: false
Tcdian commented 4 years ago

Solution

/**
 * Definition for a binary tree node.
 * function TreeNode(val, left, right) {
 *     this.val = (val===undefined ? 0 : val)
 *     this.left = (left===undefined ? null : left)
 *     this.right = (right===undefined ? null : right)
 * }
 */
/**
 * @param {TreeNode} p
 * @param {TreeNode} q
 * @return {boolean}
 */
var isSameTree = function(p, q) {
    if (p === null && q === null) {
        return true;
    }
    if (p === null || q === null) {
        return false;
    }
    return p.val === q.val && isSameTree(p.left, q.left) && isSameTree(p.right, q.right);
};
/**
 * Definition for a binary tree node.
 * class TreeNode {
 *     val: number
 *     left: TreeNode | null
 *     right: TreeNode | null
 *     constructor(val?: number, left?: TreeNode | null, right?: TreeNode | null) {
 *         this.val = (val===undefined ? 0 : val)
 *         this.left = (left===undefined ? null : left)
 *         this.right = (right===undefined ? null : right)
 *     }
 * }
 */

function isSameTree(p: TreeNode | null, q: TreeNode | null): boolean {
    if (p === null && q === null) {
        return true;
    }
    if (p === null || q === null) {
        return false;
    }
    return p.val === q.val && isSameTree(p.left, q.left) && isSameTree(p.right, q.right);
};