Open Tcdian opened 4 years ago
/**
* @param {string} num1
* @param {string} num2
* @return {string}
*/
var addStrings = function(num1, num2) {
const maxLen = num1.length > num2.length ? num1.length + 1 : num2.length + 1;
num1 = num1.padStart(maxLen, '0');
num2 = num2.padStart(maxLen, '0');
let result = '';
let curry = 0;
for (let i = maxLen - 1; i >= 0; i--) {
const sum = Number(num1[i]) + Number(num2[i]) + curry
result = sum % 10 + result;
curry = Math.floor(sum / 10);
}
let separator = 0;
while(separator !== result.length - 1 && result[separator] === '0') {
separator++;
}
return result.slice(separator);
};
function addStrings(num1: string, num2: string): string {
const maxLen = num1.length > num2.length ? num1.length + 1 : num2.length + 1;
num1 = num1.padStart(maxLen, '0');
num2 = num2.padStart(maxLen, '0');
let result = '';
let curry = 0;
for (let i = maxLen - 1; i >= 0; i--) {
const sum = Number(num1[i]) + Number(num2[i]) + curry
result = sum % 10 + result;
curry = Math.floor(sum / 10);
}
let separator = 0;
while(separator !== result.length - 1 && result[separator] === '0') {
separator++;
}
return result.slice(separator);
};
415. Add Strings
给定两个字符串形式的非负整数 num1 和num2 ,计算它们的和。
Note
num1
和num2
的长度都小于5100
.num1
和num2
都只包含数字0-9
.num1
和num2
都不包含任何前导零。