Open Tcdian opened 3 years ago
/**
* Definition for singly-linked list.
* function ListNode(val, next) {
* this.val = (val===undefined ? 0 : val)
* this.next = (next===undefined ? null : next)
* }
*/
/**
* @param {ListNode} head
* @return {void} Do not return anything, modify head in-place instead.
*/
var reorderList = function(head) {
const reversedPart = reverseList(findMidPoint(head));
mergeList(head, reversedPart);
function findMidPoint(head) {
let patrol = new ListNode(-1);
patrol.next = head;
let slow = patrol;
let fast = patrol;
while (fast !== null && fast.next !== null) {
fast = fast.next.next;
slow = slow.next;
}
if (slow !== null) {
const part = slow.next;
slow.next = null;
return part;
}
return null;
}
function reverseList(head) {
let prev = null;
while(head !== null) {
let temp = head.next;
head.next = prev;
prev = head;
head = temp;
}
return prev;
}
function mergeList(l1, l2) {
let patrol = new ListNode(-1);
while (l1 !== null && l2 !== null) {
patrol.next = l1;
l1 = l1.next;
patrol = patrol.next;
patrol.next = l2;
l2 = l2.next;
patrol = patrol.next;
}
patrol.next = l1 || l2;
}
};
/**
* Definition for singly-linked list.
* class ListNode {
* val: number
* next: ListNode | null
* constructor(val?: number, next?: ListNode | null) {
* this.val = (val===undefined ? 0 : val)
* this.next = (next===undefined ? null : next)
* }
* }
*/
/**
Do not return anything, modify head in-place instead.
*/
function reorderList(head: ListNode | null): void {
const reversedPart = reverseList(findMidPoint(head));
mergeList(head, reversedPart);
function findMidPoint(head: ListNode | null): ListNode | null {
let patrol = new ListNode(-1);
patrol.next = head;
let slow: ListNode | null = patrol;
let fast: ListNode | null = patrol;
while (fast !== null && fast.next !== null) {
fast = fast.next.next;
slow = (slow as ListNode).next;
}
if (slow !== null) {
const part = slow.next;
slow.next = null;
return part;
}
return null;
}
function reverseList(head: ListNode | null): ListNode | null {
let prev: ListNode | null = null;
while(head !== null) {
let temp = head.next;
head.next = prev;
prev = head;
head = temp;
}
return prev;
}
function mergeList(l1: ListNode | null, l2: ListNode | null) {
let patrol: ListNode | null = new ListNode(-1);
while (l1 !== null && l2 !== null) {
patrol.next = l1;
l1 = l1.next;
patrol = patrol.next;
patrol.next = l2;
l2 = l2.next;
patrol = patrol.next;
}
patrol.next = l1 || l2;
}
};
143. Reorder List
给定一个单链表 L:
L0→L1→…→Ln-1→Ln
, 将其重新排列后变为:L0→Ln→L1→Ln-1→L2→Ln-2→…
你不能只是单纯的改变节点内部的值,而是需要实际的进行节点交换。
Example 1
Example 2