Tcdian / keep

今天不想做,所以才去做。
MIT License
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404. Sum of Left Leaves #312

Open Tcdian opened 3 years ago

Tcdian commented 3 years ago

404. Sum of Left Leaves

计算给定二叉树的所有左叶子之和。

Example

    3
   / \
  9  20
    /  \
   15   7

There are two left leaves in the binary tree, with values 9 and 15 respectively. Return 24.
Tcdian commented 3 years ago

Solution

/**
 * Definition for a binary tree node.
 * function TreeNode(val, left, right) {
 *     this.val = (val===undefined ? 0 : val)
 *     this.left = (left===undefined ? null : left)
 *     this.right = (right===undefined ? null : right)
 * }
 */
/**
 * @param {TreeNode} root
 * @return {number}
 */
var sumOfLeftLeaves = function(root) {
    let result = 0;
    dfs(root);
    return result;

    function dfs(root) {
        if (root === null) {
            return;
        }
        if (root.left !== null && root.left.left === null && root.left.right === null) {
            result += root.left.val;
        }
        dfs(root.left);
        dfs(root.right);
    }
};
/**
 * Definition for a binary tree node.
 * class TreeNode {
 *     val: number
 *     left: TreeNode | null
 *     right: TreeNode | null
 *     constructor(val?: number, left?: TreeNode | null, right?: TreeNode | null) {
 *         this.val = (val===undefined ? 0 : val)
 *         this.left = (left===undefined ? null : left)
 *         this.right = (right===undefined ? null : right)
 *     }
 * }
 */

function sumOfLeftLeaves(root: TreeNode | null): number {
    let result = 0;
    dfs(root);
    return result;

    function dfs(root: TreeNode | null) {
        if (root === null) {
            return;
        }
        if (root.left !== null && root.left.left === null && root.left.right === null) {
            result += root.left.val;
        }
        dfs(root.left);
        dfs(root.right);
    }
};