Open Tcdian opened 3 years ago
/**
* Definition for a binary tree node.
* function TreeNode(val, left, right) {
* this.val = (val===undefined ? 0 : val)
* this.left = (left===undefined ? null : left)
* this.right = (right===undefined ? null : right)
* }
*/
/**
* @param {TreeNode} root
* @return {number}
*/
var sumOfLeftLeaves = function(root) {
let result = 0;
dfs(root);
return result;
function dfs(root) {
if (root === null) {
return;
}
if (root.left !== null && root.left.left === null && root.left.right === null) {
result += root.left.val;
}
dfs(root.left);
dfs(root.right);
}
};
/**
* Definition for a binary tree node.
* class TreeNode {
* val: number
* left: TreeNode | null
* right: TreeNode | null
* constructor(val?: number, left?: TreeNode | null, right?: TreeNode | null) {
* this.val = (val===undefined ? 0 : val)
* this.left = (left===undefined ? null : left)
* this.right = (right===undefined ? null : right)
* }
* }
*/
function sumOfLeftLeaves(root: TreeNode | null): number {
let result = 0;
dfs(root);
return result;
function dfs(root: TreeNode | null) {
if (root === null) {
return;
}
if (root.left !== null && root.left.left === null && root.left.right === null) {
result += root.left.val;
}
dfs(root.left);
dfs(root.right);
}
};
404. Sum of Left Leaves
计算给定二叉树的所有左叶子之和。
Example