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PS2 vs PS1 notation for power series #41

Open owensks opened 11 months ago

owensks commented 11 months ago

Definition 9.1.1 defines a power series as centered at x=c, where the coefficients are a sequence {a_n}. I guess this makes sense because then the center is x=c, and the coefficients are a numeric sequence {a_n} like we've seen in all the previous sections. I guess "c" stands for center.

But then we get to Remark 9.2.1, which then switches what was the center x=c to be the center x=a, and switches the coefficient sequence {a_n} to be a coefficient sequence {c_n}. I guess "c" stands for coefficient.

Remark 9.2.1 uses coefficients c_n but then links back to Fact 8.7.1 which uses coefficients a_n.

Long story short, I think it would probably be good to rewrite this section to agree with coefficients being {a_n} and power series defined by (x-c)^n. Having (x-a)^n with {c_n} sometimes but then (x-c)^n with {a_n} other times is not ideal.

(edit: If y'all agree it is a good idea to switch the centers in PS2 to be consistent with PS1, PS3, and PS4, then I will go through and make the edits and push them)

StevenClontz commented 11 months ago

I have no opinion other than agreeing they should all be consistent in our book.

(And that I appreciate Kate's diligence in opening these issues and am very happy we have a collaborative team working on the library!)

siwelwerd commented 11 months ago

I agree it would be good to be consistent! I think I prefer a_n for coefficients and c for center.

owensks commented 11 months ago

So I spent some time thinking about this last night. To do IOC or ROC, students compute \( \lim_{n \to \infty} \frac{a_{n+1}}{a_n}} \) but in this case the a_n are really of the form \( b_n = a_n (x-c)^n \) and our letters are confused, again. Perhaps it would make sense to call something a power series if it has terms of the form ( bn (x-c)^n ) and then to find the radius of convergence we compute `( \lim{n \to \infty} \frac{a_{n+1}}{a_n}} )where a_n is defined as( a_n = b_n (x-c)^n )`

Are students going to be confused about why the Ratio Test has a_n without any (x-c)^n, then power series are a_n (x-c)^n, but we're still doing the Ratio Test? Somehow we are composing a_n with a function that already contains a_n.

TL;DR What do you think about defining power series as \series b_n (x-c)^n everywhere

StevenClontz commented 11 months ago

I don't think in practice when students see

$$\sum_{n=0}^\infty \frac{x^n}{n+1}$$

that they think "oh here we have $a_n=\frac{1}{n+1}$ as part of the power series definition". It only comes up once they're checking endpoints

$$\sum_{n=0}^\infty \frac{1}{n+1}$$

$$\sum_{n=0}^\infty \frac{(-1)^n}{n+1}$$

and in these cases the power series definition is irrelevant?

owensks commented 11 months ago

Sounds good. I'll make the changes to PS2 and push them. Pull them? Merge them? Click the buttons in the right spot them. 😁

StevenClontz commented 11 months ago

(As a mostly irrelevant aside: I would not be sad if we ditched endpoints of intervals of convergence, or pushed them to the back of the section so they can be skipped.)

fragandi commented 2 months ago

I am interested in looking this over and closing this, let me know if anyone has updates on their opinions!

siwelwerd commented 2 months ago

I suggest just going ahead and implementing without waiting for additional opinions. We've had a 9 month waiting period on this one for folks to say anything they wanted to say about it.