mvandervoord
commented
10 months ago I'm confident you've misdiagnosed what is happening here. Likely you've just missed a detail somewhere. Is it actually this example or is this a simplified version of the problem? If the latter, some things to double check:
- perhaps it's not actually marked
static? - perhaps there's an off-by-one error and you're calling the function 1 too-few many times?
- perhaps printf is getting eaten up somewhere in the process... try changing the print to something that sets a flag or something to verify?
Unity does a lot of tricky stuff in the background, but it can't change the rules of C for you. If you've marked a variable as static in your release function, it's still static and Unity can't touch it.
joe-ju
Hi, I implemented a test function in unity like: / tests / void test_helloworld(void) { target_fun(); target_fun(); }
And the target function implementation in my source is the following: void target_func(void) { static in i = 0; if (++i >=2) printf("hello world\n"); }
The print never happened and after some investigation, when target_fun() is invoked for the second time the "i" was reset to 0 again, but I also tested target_func(void) in the same way without unity and it worked. Do you have any idea about this test in unity? Thanks!