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Tomius / auto_derive

C++14 automatic differentiation
MIT License
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Cannot Compile in g++-6 #1

Closed rcalxrc08 closed 7 years ago

rcalxrc08 commented 7 years ago

Hi, hi cannot compile you simple example about your library, the compiler states: fatal error: ./cpp14.hpp: No such file or directory. I don't understand where that file should be. I also tried to delete that include but then the compiler don't recognize enable_if_t statement. I am compiling using g++-6 6.3.0. I am using Linux Mint 18.1. I obviusly added the right flag to the compiler, i.e. -I../ -Icore/ -Itest -std=c++14. Do you have any idea?

Tomius commented 7 years ago

Hi rcalxrc08,

Thank you for letting me know this issue.

It seems that I forgot to commit that file, but there was only a using statement in it, like this:

template< bool B, class T = void >
using enable_if_t = typename std::enable_if<B,T>::type;

I first wanted this library to use c++11, not c++14, so I had to define this myself, and I somehow left it there.

Anyway, this issue seems to be fixed with the 2d78f536587a129ba3f4c220a223cd15758417db commit I just made.