Problem: TileCondition (used by QueueTask.waitTile(Tile) does not work correctly.
Symptom: Tile properties that are used in Tile.sameAs(Tile) are val thus cannot be changed. When a Tile was passed to TileCondition as src. It seems as though the intention was for src to update as a reference the properties update, but the properties will never update (because they are val), thus rendering TileCondition useless.
Solution: TileCondition now takes Pawn and Tile (TileCondition(Pawn, Tile)), and since Pawn.tile is a var it means that it changes as Pawn.tile changes, and it allows TileCondition to work as expected.
QueueTask.waitTile(tile: Tile) has been changed to QueueTask.waitTile(tile: Tile, pawn: Pawn = ctx as Pawn) to keep backwards compatibility and preserve previous functionality while also giving the developer a bit more control over which Pawn they want to reach the tile before continuing the logic.
Problem:
TileCondition(used byQueueTask.waitTile(Tile)does not work correctly.Symptom:
Tileproperties that are used inTile.sameAs(Tile)arevalthus cannot be changed. When aTilewas passed toTileConditionassrc. It seems as though the intention was forsrcto update as a reference the properties update, but the properties will never update (because they areval), thus renderingTileConditionuseless.Solution:
TileConditionnow takesPawnandTile(TileCondition(Pawn, Tile)), and sincePawn.tileis avarit means that it changes asPawn.tilechanges, and it allowsTileConditionto work as expected.QueueTask.waitTile(tile: Tile)has been changed toQueueTask.waitTile(tile: Tile, pawn: Pawn = ctx as Pawn)to keep backwards compatibility and preserve previous functionality while also giving the developer a bit more control over whichPawnthey want to reach the tile before continuing the logic.