I can't use google rich snippet in a popup

[GoogleCodeExporter]

What steps will reproduce the problem?
1.Create a Javascript popup using window.open() function
2.Generate HTML code(using PHP) in the popup
3.HTML have snippet informations

What is the expected output? What do you see instead?
When I click on the google +1 button I only see the title of the page and the 
paragraph identified by "<p>" tags.
I have typed all is mentionned in the documentation to display snippet.

What version of the product are you using? On what operating system?
I tried it throw Firefox 14.0.1 using Linux operating system

Please provide any additional information below.
You can find the code running at 
https://www.users.prplk.com/users/modulesNav/genererLien.php

This code is working well in this link(it is a copy/paste of what I have in my 
popup). But I don't understand why it doesn't work in my popup.

I hope someone have a solution to my problem.

Regards.

Original issue reported on code.google.com by l.lafo...@gmail.com on 27 Jul 2012 at 8:00

[GoogleCodeExporter]

Can you link to a popup?

Original comment by 4braham on 27 Jul 2012 at 10:53

[GoogleCodeExporter]

I can't link you to the popup because it is a firefox extension which open the 
popup. I resolved the problem by adding a php session constant variable: 
$_SESSION['idSite'] = 240;
I really don't know where is the problem because I never use this variable and 
if I don't put this line at the begining of my code the snippet doesn't work.

Original comment by l.lafo...@gmail.com on 29 Jul 2012 at 6:16

[GoogleCodeExporter]

I have problem I can't use rich snippets anyone can help

Original comment by murhmta...@gmail.com on 23 Oct 2012 at 3:23

[GoogleCodeExporter]

Original comment by joannasm...@google.com on 3 Apr 2013 at 8:03

• Added labels: Component-Plugins
• Removed labels: Priority-Medium