Open marcbezem opened 3 years ago
Probably the "degree 0 map" is defined as the constant map to the basepoint.
By the way, another possible definition for a constant function f would be one with an identification with one of the form x |-> b. Then it would be a mathematical definition.
Actually, Exercise 3.3.3 (2) seems wrong now: how to prove that all fibers are sets?
@DanGrayson the text suggests δ_0 is defined by circle induction to be constant, so definitionally different from the "constant map".
I found the definition finally in 3.6.3. And you are right -- it's not a "constant map". But it can be identified with one.
I've tweaked the definition of constant maps (to what was intended): a map equal to one of the form …
As for Ex. 3.3.3(2): It is solvable as stated. To avoid spoilers, I won't write the solution here in public, but I'll email you one if necessary :)
@DanGrayson sorry for lettting you search, will add "degree" to the index @UlrikBuchholtz thanks, and this is the second time I stumble over Ex. 3.3.3 (2). Will try harder, or search for your previous answer :-)
Still, Ex. 3.3.3 does not directly apply to the degree 0 function, factoring through type 1 doesn't give the negative result.
In some cases one wants the definitional variant of constancy, for example here: "transport in a constant type family is the identity". Not sure there are such cases in the book now, though.
We currently have "constant map, which is one of the form x |→ b". The "of the form" seems to refer to the definition. Would the degree 0 function, which happens to be constant, also be "a constant map"? Somewhat related, Exercise 3.3.3 does (after some changes) not longer directly apply to the degree 0 function. This should be fixed, either in the exercise or in the statement about the degree 0 function.