bandwidth parameter

[wggegshjg]

dear author I want to know where to set the subbandwidth parameters of the eNodeB and gNodeB; I want to set different bandwidth for two types of BS； for example, .carrierAggregation.componentCarrier[0].carrierFrequency=2GHz .carrierAggregation.componentCarrier[0].numBands=50 .carrierAggregation.componentCarrier[1].carrierFrequency=28GHz .carrierAggregation.componentCarrier[1].numBands=50 and Each vehicle（0） can obtain 10Mhz bandwidth； Each vehicle（1） can obtain 100Mhz bandwidth；

[wggegshjg]

when i measurement end-end delay，The delay of using a 4g（only） base station is 15ms； and The delay of using a 5g（only） base station is 14.5ms ； In comparison, 5g has no advantage

[giovanninardini]

dear author I want to know where to set the subbandwidth parameters of the eNodeB and gNodeB; I want to set different bandwidth for two types of BS； for example, .carrierAggregation.componentCarrier[0].carrierFrequency=2GHz .carrierAggregation.componentCarrier[0].numBands=50 .carrierAggregation.componentCarrier[1].carrierFrequency=28GHz .carrierAggregation.componentCarrier[1].numBands=50 and Each vehicle（0） can obtain 10Mhz bandwidth； Each vehicle（1） can obtain 100Mhz bandwidth；

The numBands parameter controls the bandwidth. It is the number of Resource Blocks assigned to that specific carrier. For example, with 4G and 5G with numerology 0, "50 RBs" mean 10MHz bandwidth, "100 RBs" mean 20MHz bandwidth, and so on.

[giovanninardini]

when i measurement end-end delay，The delay of using a 4g（only） base station is 15ms； and The delay of using a 5g（only） base station is 14.5ms ； In comparison, 5g has no advantage

This is probably because, by default, 5G is configured with numerology 0 (i.e., one TTI is 1 ms, just like 4G). You can try to change the numerology by setting the numerologyIndex parameter (can be one number between 0 and 4), for example:

*.carrierAggregation.componentCarrier[0].numerologyIndex=1

[wggegshjg]

参数控制带宽。它是分配给该特定运营商的资源块数。例如，对于命理为 0 的 4G 和 5G，“50 RUB”表示 10MHz 带宽，“100 RUB”表示 20MHz 带宽，依此类推。

thanks This means that the RB of each 4G and 5G BS has the same resource; Each RB occupies 0.2Mhz。

[wggegshjg]

当测量端到端延迟时，使用4g（仅）基站的延迟为15ms;使用5g（仅）基站的延迟为14.5ms;相比之下，5G没有优势

这可能是因为默认情况下，5G配置了命理0（即，一个TTI是1毫秒，就像4G一样）。您可以尝试通过设置参数（可以是 0 到 4 之间的一个数字）来更改命理，例如：numerologyIndex

`*.carrierAggregation.componentCarrier[0].numerologyIndex=1 i will try more numerologyIndex

[giovanninardini]

参数控制带宽。它是分配给该特定运营商的资源块数。例如，对于命理为 0 的 4G 和 5G，“50 RUB”表示 10MHz 带宽，“100 RUB”表示 20MHz 带宽，依此类推。

thanks This means that the RB of each 4G and 5G BS has the same resource; Each RB occupies 0.2Mhz。

according to the 3GPP standard, one RB occupies 180KHz (with 4G and 5G with numerology index 0)

[shashini-w]

dear author I want to know where to set the subbandwidth parameters of the eNodeB and gNodeB; I want to set different bandwidth for two types of BS； for example, .carrierAggregation.componentCarrier[0].carrierFrequency=2GHz .carrierAggregation.componentCarrier[0].numBands=50 .carrierAggregation.componentCarrier[1].carrierFrequency=28GHz .carrierAggregation.componentCarrier[1].numBands=50 and Each vehicle（0） can obtain 10Mhz bandwidth； Each vehicle（1） can obtain 100Mhz bandwidth；

The numBands parameter controls the bandwidth. It is the number of Resource Blocks assigned to that specific carrier. For example, with 4G and 5G with numerology 0, "50 RBs" mean 10MHz bandwidth, "100 RBs" mean 20MHz bandwidth, and so on.

Dear Mr. @giovanninardini,

Could you please explain how this relationship between RBs and the Bandwidth (num bands/5 = Bandwidth in MHz) is derived? I want to use a different numerology and as you have told this is only valid for numerology 0, I want to know how to calculate the Bandwidth in that case based on the num bands.

Because I tried to rebuild the relation and for example, if I have set num bands =50 with numerology 0, then No. of RBs = 50 No. of subcarriers = 50 12 = 600. Transmission Bandwidth = No.of subcarriers subcarrier spacing = 600*15 kHz = 9 MHz. Is the guard band set to be 500kHz to make the channel Bandwidth = 10MHz ? (I suppose in your explanation you meant channel Bandwidth is 10MHz)

[giovanninardini]

Hello,

Your calculations are correct. You should consider 10% of the bandwidth as reserved for guard bands (1MHz in case of 10 MHz channel bandwidth).

[shashini-w]

Hello,

Your calculations are correct. You should consider 10% of the bandwidth as reserved for guard bands (1MHz in case of 10 MHz channel bandwidth).

Thank you! So this means the generalized relationship is : Channel Bandwidth in MHz = (num bands/5) * 2^numerology index with 10% of the bandwidth reserved for guard bands