lhughey
commented
6 years ago My attempt at getting rendering a SliderMenuView from XAML (from scratch) is below
` <?xml version="1.0" encoding="UTF-8"?> <slideOverKit:MenuContainerPage xmlns="http://xamarin.com/schemas/2014/forms" xmlns:x="http://schemas.microsoft.com/winfx/2009/xaml" xmlns:slideOverKit="clr-namespace:SlideOverKit;assembly=SlideOverKit" x:Class="SlideOverKit.MoreSample.InnerMenuPage"> <slideOverKit:SlideMenuView HorizontalOptions="End" MenuOrientations="RightToLeft" IsFullScreen="False" BackgroundViewColor="Transparent" BackgroundColor="Red" WidthRequest="200" HeightRequest="500" DraggerButtonWidth="50" TopMargin="30" x:Name="myMenu">
</slideOverKit:SlideMenuView> </slideOverKit:MenuContainerPage>
`
Can someone show me how they are able to get the RightToLeft Slider working using only XAML? I'd like to invoke the SliderMenu from XAML but i've been unsuccessful. I removed the following line from the .cs codebhind
SlideMenu = new QuickInnerMenuView(MenuOrientation.RightToLeft);And replaced it with
`
`
then changed the codebehind to call the XAML quickinnerMenuView
SlideMenu = new QuickInnerMenuView(MenuOrientation.RightToLeftSlideMenu = myMenu;It immediately threw the error that I needed the input the HeightRequest, which is odd considering i'm calling the same object which has that property defined in its constructor. I'm now dealing with a duplicate sliders on the page. I had originally planned on constructing the entire SliderMenuView from XAML, but i once again ran into multiple items.
Can someone show me how they are able to get the RightToLeft Slider working using only XAML? I have complicated screen that would work best keeping the design consistent with XAML.