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正则表达式 #23

Open Yang03 opened 5 years ago

Yang03 commented 5 years ago

前向声明

?=
'abcacad'.replace(/a(?=b)/g,'*') //*bcacad

反前向声明

'abcacad'.replace(/a(?!b)/g,'*') //abc*c*d
let str="123456789";
let  re=/(?=(?!(\b))(\d{3})+$)/g
str=str.replace(re, ",")
console.log(str)

\b 是单词边界