Closed george-kuanli-peng closed 1 year ago
Workaround: pass the "asyc" parameter with a dictionary and unpack the dictionary with **
.
Yeah... Unfortunately the mentioned workaround is the only option available. Closing this as a solution to the issue has been communicated already
How do I make a request with a sanitizing name
async
?async
is a Python reserved keyword and cannot be used in keyword arguments.