Closed GoogleCodeExporter closed 9 years ago
For the record, tell me exactly what INERT/COLDWALL does.
Original comment by gfor...@gmail.com
on 3 Dec 2008 at 8:26
It is a solid surface that maintains the ambient temperature.
Original comment by mcgra...@gmail.com
on 3 Dec 2008 at 8:38
so, heat transfer to or from this surface still occurs based upon its
temperature
being at ambient? Hence jason's suggestion to change the name to COLDWALL.
Original comment by gfor...@gmail.com
on 3 Dec 2008 at 8:49
Yes. Or maybe not COLDWALL but AMBIENT_WALL or something that more actually
reflects what the surface really is.
Original comment by drjfloyd
on 3 Dec 2008 at 8:58
Is not an INERT wall the same as an ISOTHERMAL wall, a wall with fixed
temperature ?
Original comment by Finn.Dra...@gmail.com
on 4 Dec 2008 at 2:09
Yes, the wall is ISOTHERMAL, but I would rather not use that term because we
use it
already on the MISC line, meaning that there are no temperature changes allowed
in
the calculation.
Original comment by mcgra...@gmail.com
on 4 Dec 2008 at 2:22
in the original FDS the default condition was adiabatic.in fact it said is an
adiabatic, inert wall. i'm sure the default has been changed for some time now.
But
i need some clarification on this now as well.
my understanding from the discussions and User manual is that the Inert
boundary
condition absorbs heat based on the temperature gradient between the gas
temperature
and 20deg but doesn't heat up . how much heat does the inert surface absorb or
what
it is similar to e.g. concrete, block since you've suggested replacing with
coldwall?
Original comment by adrienne...@gmail.com
on 19 Jan 2009 at 6:10
The original version assumed that there was no convective heat transfer to an
INERT
wall -- that is, the wall was the same temperature as the gas. This assumption
was
based on the fact that most building materials have low thermal conductivities
and
are good insulators.
We kept the name INERT, even though now it refers to an ambient temperature
solid.
The heat transfer to it is
q" = eps*sigma*(T_eff^4-T_amb^4) + h*(T_g-T_amb)
where T_eff is the "effective" gas temperature from the standpoint of radiation
transport and T_g is the near wall gas temperature. T_eff is not calculated
explicitly, but rather a detailed radiation heat transfer calculation is used
to
predict the radiative heat flux to the wall.
Think of an INERT solid as something that never heats up, like a piece of steel
that
has cold water constantly flowing across its back side. We recommend that this
BC
not be used -- it is better to assign actual material properties to everything.
But
we have to have a default nonetheless.
Original comment by mcgra...@gmail.com
on 21 Jan 2009 at 1:43
before releasing 5.4.0, do we wish to take action on changing INERT to
something more
meaningful?
Original comment by drjfloyd
on 9 Jun 2009 at 8:32
If you do, INERT should still work. Maybe just alias it somehow. I think most
people
have become aware of INERT means. Changing it might confuse things more.
Original comment by mcgra...@gmail.com
on 9 Jun 2009 at 9:17
No real groundswell of support for or against the idea, so I won't take any
action.
Original comment by drjfloyd
on 27 Jul 2009 at 12:50
Original issue reported on code.google.com by
drjfloyd
on 3 Dec 2008 at 8:05