Closed lambdacalculator closed 1 year ago
After
Theorem test : forall (A B:o) L, member A L -> member B L -> member A L. intros H1.
the proof state is
Variables: A B L H1 : member A L H1 : member B L ============================ member A L
At this point both clear H1 and case H1 remove both hypotheses (but the latter does inversion on the first).
clear H1
case H1
After
the proof state is
At this point both
clear H1
andcase H1
remove both hypotheses (but the latter does inversion on the first).