Open SiriSVC opened 4 years ago
Hi @SiriSVC ,
you will have to loop over the list chars
, apply the change_url()
function to each string contained in chars
and append each processed string to the list answer_050
. In your current code you apply the function to the whole list which is not what you want :)
Thanks Jonas :)
However I still cannot get it right... I receive TypeError: 'str' object is not callable to the following code:
chars = ["en", "da"] # initialize list outside the main loop
for x in (chars): #loop over the list chars change_url = change_url(x) #apply the change_url() function to each string contained in chars answer_50.append(change_url(x)) #and append each processed string to the list answer_050 print(answer_50)
:)
Hi @SiriSVC,
you are storing the processed string in a variable with the same name as the function in this line:
change_url = change_url(x) #apply the change_url() function to each string contained in chars
As such, when you write answer_50.append(change_url(x))
you are trying to use the string that you just stored in change_url
as a function, but the variable is not pointing to a function anymore but a string and therefore it throws the TypeError.
Store the processed string in a variable named something different, e.g. processed_string
.
Then you can append the variable processed_string
to the list and everything should be fine :)
ahh yes :) THANKS! - now it works (at least the output does).
The assert line raises an error, when I run the following code:
chars = ["en", "da"] answer_050 = change_url(chars) print(answer_050)
I am not sure what the error is, but I am sure my code is wrong since the output doesn’t come out as a list with the url in the languages contained in the list.
Do you know how to fix it? Thanks :)