Rrr

[ackermanmoriii]

import os
from docx import Document

def extract_student_name(text):
    """
    This function extracts the student name between "نام دانشجو:" and the next period ".".
    """
    start_marker = "نام دانشجو:"
    end_marker = "."

    try:
        start_idx = text.index(start_marker) + len(start_marker)
        end_idx = text.index(end_marker, start_idx)
        student_name = text[start_idx:end_idx].strip()
        return student_name
    except ValueError:
        return None

def process_word_files(source_folder, destination_folder):
    """
    This function processes all Word files in the source folder, extracts student names, 
    and moves files to new folders named after the extracted student names.
    """
    if not os.path.exists(destination_folder):
        os.makedirs(destination_folder)

    for filename in os.listdir(source_folder):
        if filename.endswith(".docx"):
            filepath = os.path.join(source_folder, filename)
            try:
                doc = Document(filepath)
                full_text = []
                for para in doc.paragraphs:
                    full_text.append(para.text)
                combined_text = "\n".join(full_text)

                student_name = extract_student_name(combined_text)
                if student_name:
                    # Create a new folder named after the student
                    student_folder = os.path.join(destination_folder, student_name)
                    if not os.path.exists(student_folder):
                        os.makedirs(student_folder)

                    # Move the Word file to the new folder
                    new_filepath = os.path.join(student_folder, filename)
                    os.rename(filepath, new_filepath)
                    print(f"Moved {filename} to {student_folder}")
                else:
                    print(f"Could not find a student name in {filename}")
            except Exception as e:
                print(f"Error processing file {filename}: {e}")

if __name__ == "__main__":
    # Define source and destination folders
    source_folder = "path/to/source/folder"  # Update this with the path to your source folder
    destination_folder = "path/to/destination/folder"  # Update this with the path to your destination folder

    # Process the Word files
    process_word_files(source_folder, destination_folder)

[ackermanmoriii]

Let’s walk through a simple numerical example to illustrate short-run versus long-run elasticity using the same gasoline example.

Scenario: Gasoline Prices

• Initially, the price of gasoline is $2 per gallon.
• People in a city are buying 1,000 gallons of gasoline per day at this price.

Now, the price increases to $4 per gallon. How do people respond in the short run versus the long run?

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1. Short-Run Response

In the short run, people can’t change their habits quickly (they still need to drive the same amount).

• At $4 per gallon, people reduce their consumption a little because the price has doubled, but they still buy 900 gallons per day.

Short-Run Elasticity Calculation

Elasticity formula:

[ \text{Elasticity} = \frac{\%\ \text{change in quantity demanded}}{\%\ \text{change in price}} ]

Step 1: Calculate the percentage change in price

• The price increased from $2 to $4, so:

[ \%\ \text{change in price} = \frac{4 - 2}{2} \times 100 = 100\% ]

Step 2: Calculate the percentage change in quantity demanded

• The quantity decreased from 1,000 gallons to 900 gallons:

[ \%\ \text{change in quantity demanded} = \frac{900 - 1000}{1000} \times 100 = -10\% ]

Step 3: Calculate short-run elasticity [ \text{Short-run elasticity} = \frac{-10\%}{100\%} = -0.1 ]

This tells us that in the short run, gasoline is inelastic (-0.1), meaning demand doesn’t change much when the price increases.

---

2. Long-Run Response

In the long run, people have time to adjust to higher prices. Over time, they start buying more fuel-efficient cars, using public transport, or moving closer to work.

• At $4 per gallon, people reduce their consumption more significantly, now only buying 700 gallons per day.

Long-Run Elasticity Calculation

Step 1: Percentage change in price remains the same as before: 100% (from $2 to $4).

Step 2: Calculate the percentage change in quantity demanded

• The quantity now decreased from 1,000 gallons to 700 gallons:

[ \%\ \text{change in quantity demanded} = \frac{700 - 1000}{1000} \times 100 = -30\% ]

Step 3: Calculate long-run elasticity [ \text{Long-run elasticity} = \frac{-30\%}{100\%} = -0.3 ]

In the long run, gasoline is more elastic (-0.3) because people have had time to make adjustments, and demand decreases more when the price increases.

---

Summary

• Short-run elasticity: -0.1 (Inelastic: people don’t reduce consumption much at first).
• Long-run elasticity: -0.3 (More elastic: over time, people reduce consumption more).

This shows how people’s ability to adjust over time changes the elasticity of demand!