Closed Andromeda606 closed 2 years ago
@Andromeda606 do you realize that “isPrototypeOf” requires “P” to get that word?
@Andromeda606 do you realize that “isPrototypeOf” requires “P” to get that word?
'd': '(undefined+"")[2]',
the same is heard here.
the same is heard here.
No, it is completely different: “undefined”
is an “atomic” construct that does not require any letters — [][[]]+[]
.
aynısı burada da duyuluyor.
Hayır, tamamen farklıdır:
“undefined”
herhangi bir harf gerektirmeyen “atomik” bir yapıdır —[][[]]+[]
.
I understand.
I don't know if anyone has said that, but this gives the result P.