Problem : https://github.com/akamhy/foo-bar-is-real is 404. I am requesting an archive for an URL that doesn't exist and therefore ain't archived on wayback machine.
The following text is not helpful to folks who don't know python. And looks unprofessional from CLI point of view.
$ waybackpy --oldest --url https://github.com/akamhy/foo-bar-is-real
Traceback (most recent call last):
File "/home/akamhy/anaconda3/bin/waybackpy", line 8, in <module>
sys.exit(main())
File "/home/akamhy/.local/lib/python3.8/site-packages/waybackpy/cli.py", line 254, in main
output = args_handler(args)
File "/home/akamhy/.local/lib/python3.8/site-packages/waybackpy/cli.py", line 138, in args_handler
return _oldest(obj)
File "/home/akamhy/.local/lib/python3.8/site-packages/waybackpy/cli.py", line 25, in _oldest
return obj.oldest()
File "/home/akamhy/.local/lib/python3.8/site-packages/waybackpy/wrapper.py", line 202, in oldest
return self.near(year=year)
File "/home/akamhy/.local/lib/python3.8/site-packages/waybackpy/wrapper.py", line 184, in near
raise WaybackError(
waybackpy.exceptions.WaybackError: Can not find archive for 'https://github.com/akamhy/foo-bar-is-real' try later or use wayback.Url(url, user_agent).save() to create a new archive.
akamhy
commented
3 years ago
Problem : https://github.com/akamhy/foo-bar-is-real is 404. I am requesting an archive for an URL that doesn't exist and therefore ain't archived on wayback machine.
The following text is not helpful to folks who don't know python. And looks unprofessional from CLI point of view.