Closed harshaxnim closed 2 years ago
Right, I was confused as well when reading your issue, and I would have agreed with you. However, I did the working out, and this is why it's an O(dt^2).
As you noticed, Equation 5 is the difference of equations 2 and 3. As such, the jerk term does not cancel out, because of their different signs.
Thus (using dt
instead of delta t
): x(t + dt) - x(t-dt) = 2 v(t) dt + 1/3 b(t) dt^3 + O(dt^4)
.
Solving for v(t)
, we get: v(t) = [x(t + dt) - x(t - dt)] / (2 dt) - 1/6 b(t) dt^2 + O(dt^3)
.
However, since we don't use the jerk in the computation, it is lumped in a O(dt^3)
at the start.
As such, we have a O(dt^3)
in the difference step, and thus only a O(dt^2)
term in the velocity.
Hope this helped!
I think this should be explicitly mentioned. I'll do that today.
@Amaras Ah, yes. It's a mistake on my part! That makes perfect sense, thank you!
@leios that sounds great. Maybe I'll leave this open for you to track and close when you're done?
Hi team,
This is regarding the Verlet Integration page that's here: https://www.algorithm-archive.org/contents/verlet_integration/verlet_integration.html
Similar to how Equation 4 is sum of Eq. 2 and 3, we can see that Eq. 5 is a difference of 2 and 3. When we do that, the error term turns out to be O(del. t^3) and not O(del. t^2) as stated in the page. Did I get something wrong? Or should that page be corrected? Happy to provide more information if this post is not clear.
Best, Harsha