序列化scala的immutable.Map异常

[onelogistics]

使用fastjson序列化map,代码如下

val map=Map("test1" -> "aa")
val result=com.alibaba.fastjson.JSON.toJSONString(map,Array.empty[SerializerFeature]:_*)
println(result)

输出结果为： {"empty":false,"traversableAgain":true}

[onelogistics]

使用scala.util.parsing.json可以得到预期输出

 val map=Map("test1" -> "aa")
  val result=scala.util.parsing.json.JSONObject.apply(map)
println(result)

输出结果为： {"test1" : "aa"} 想请教下fastjson序列化异常的原因

[huangyunbo]

@Robert114 I have the same problem. How can I solve it?

[onelogistics]

i didn't solve it. fastjson is designed for Java, maybe it has some special usage on scala

[plokhotnyuk]

@junjun-yang @huangyunbo you can use jsoniter-scala for that, having the same or better efficiency in parsing and serialization but with support of Scala case classes and collections, until Scala support will land for fastjson.

[onelogistics]

okay,thank you for your.recommendation

[echohlne]

异常的原因如下: 假设val map = Map("key" -> 1) map的className为: scala.collection.immutable.Map$Map1 scala在获取当前对象匹配的ObjectSerializer时， 会根据当前类的className跟已知对象类型(比如Integer, Map， Array等) 比较, 判断传入的对象类型是否跟已知类型相同， 或者是否是对应的子类等。 Scala中的Map类型在匹配完所有已知类型后都没有发现对应的ObjectSerializer类， 最终使用了默认的JavaBeanSerializer(com\alibaba\fastjson\serializer\SerializeConfig.class$getObjectWriter), 导致错误

[yangyongyongyong]

没有解决办法吗. 就用fastjson的话