Question: Is it possible to get both accessToken and authorization code with only one user sign-in?

[JoeVanGundy]

Google has grantOfflineAccess which returns the authorization code. However, if I make this call on my own, it prompts the user to sign in again.

Is it/would it be possible to allow both "id_token" and "code" as responseTypes?

[ahmad-punch]

Any update here guys??

[ShehabSN]

Same question here, I plan on making additional api calls so i need the authorization code to exchange to tokens but I also need the id_token since im using firebase and Its needed to sign in with the id token as a credential. From the docs it seems its not possible to get both at the same time...

[flandrade]

@JoeVanGundy It's not possible, but you can use your one-time authorization code to get the accessToken. You can get more details of this workflow here:

To use Google services on behalf of a user when the user is offline, you must use a hybrid server-side flow where a user authorizes your app on the client side using the JavaScript API client and you send a special one-time authorization code to your server. Your server exchanges this one-time-use code to acquire its own access and refresh tokens from Google for the server to be able to make its own API calls

Here is a quick code snippet for Node.js:

const {OAuth2Client} = require('google-auth-library');

function getCredentials(code, scope) {
  return new Promise((resolve, reject) => {
    // create an oAuth client to authorize the API call
    const oAuth2Client = new OAuth2Client(
      YOUR_CLIENT_ID,
      YOUR_CLIENT_SECRET,
      YOUR_REDIRECT_URL
    );

    // Generate the url that will be used for the consent dialog.
    const authorizeUrl = oAuth2Client.generateAuthUrl({
      access_type: 'offline',
      scope
    });

    // Verify the integrity of the idToken through the authentication code and use the user information contained in the token
    const {  refresh_token, access_token } = await client.getToken(code)?.tokens;

    ...
}

I hope this helps!