Range error: out of bounds, when trying to open the .splat file as url

[absaravanan]

I was able to view my .ply file in the viewer and also download the model.splat file. But when I try to open the model.splat as a hosted URL it throws range error.

[absaravanan]

I figured it out. My download API was not returning Content-Length

[krishnaagarwal781]

I wanted to express my gratitude for your recent contributions to the community, particularly regarding your assistance with resolving the Content-Length issue in your download API. Your efforts have been truly valuable.

I'm currently facing a similar issue in which I'm attempting to access an API directly from a URL by modifying the path name and extracting content using the following code

However, when I alter the pathname, it fails to return any content, even though I believe the path is accurate:

If it's necessary to host and then access a specific file, like "truck.splat," could you kindly provide details on how you achieved this in your case? Your insights would be greatly appreciated.

Thank you once again for your assistance.

[absaravanan]

Here is a simple file hosting service that I used. I hosted it behind nginx with CORS enabled.

from fastapi import FastAPI, UploadFile, File, HTTPException
from fastapi.responses import FileResponse
import os
import shutil
from fastapi.responses import StreamingResponse

app = FastAPI()

# Directory to store uploaded files
UPLOAD_DIR = "uploads"

@app.post("/upload/")
async def upload_file(file: UploadFile):
    try:
        # Ensure the upload directory exists
        os.makedirs(UPLOAD_DIR, exist_ok=True)

        # Save the uploaded file to the upload directory
        with open(os.path.join(UPLOAD_DIR, file.filename), "wb") as f:
            shutil.copyfileobj(file.file, f)

        return {"message": "File uploaded successfully", "filename": file.filename}
    except Exception as e:
        raise HTTPException(status_code=500, detail=str(e))

@app.get("/download/{filename}")
async def download_file(filename: str):
    try:
        # Check if the file exists in the upload directory
        file_path = os.path.join(UPLOAD_DIR, filename)
        if not os.path.exists(file_path):
            raise HTTPException(status_code=404, detail="File not found")

        # Get the size of the file
        file_size = os.path.getsize(file_path)
        print(file_size)

        # Return the file as a StreamingResponse with the Content-Length header set
        return StreamingResponse(
            open(file_path, "rb"),
            headers={
                "Content-Disposition": f"attachment; filename={filename}",
                "Content-Length": str(file_size),
            },
            media_type="application/octet-stream",  # Adjust media type as needed
        )
    except Exception as e:
        raise HTTPException(status_code=500, detail=str(e))

if __name__ == "__main__":
    import uvicorn
    uvicorn.run(app, host="0.0.0.0", port=9000)

[krishnaagarwal781]

Thank you for your response. Since I'm at a beginner level, I require some additional assistance. I've successfully set up my FastAPI server, and it's currently running at http://127.0.0.1:8000/. However, when I attempt to run the command uvicorn main:app --host 0.0.0.0 --port 9000 --reload, I encounter a "page not found" error. At present, my server is operational using the FastAPI code you provided. What steps should I take next?

I've also uploaded my "truck.splat" file, and I'd like to access it from the frontend using a URL like http://127.0.0.1:5500/truck, where the "splat view" should display the 3D truck model. Below are the relevant code snippets:

Frontend JS code:

Backend FastAPI code:

My "truck.splat" file is located in the upload folder and appears like this:

I would greatly appreciate your guidance on this matter.

[krishnaagarwal781]

@absaravanan It would be appreciated if you spare some amount of your precious time for the issue i am facing.