Closed WhiteSong666 closed 7 months ago
The ADS1262 may not be "REAL 32-BIT ADC" as you think, there will be some noise, drift, and non-linearity.
According to the benchmark by xdevs.com/review/ti_ads1262_p1, ADS1262 may have "Slightly better" data quality than general 24-Bit ADCs, and the remaining bits are basically random noise.
To summarize, discard 5 of the 32 bits is a compromise that allows Explorer to output data in 27 bits, and can still get pretty good results.
I'm using the ads1256 and I don't think I need to give up those 5 bits of data. But if I don't shift 5 bits to the right, the anyshake Observer's waveform is 32 times smaller, but the gal is normal. If I shift 5 bits to the right, the anyshake Observer's waveform is normal, but the gal is 32 times larger.
You need to change the attributes of adc_settings
field in AnyShake Observer's configuration to adapt your actual settings.
You need to change the attributes of
adc_settings
field in AnyShake Observer's configuration to adapt your actual settings.
See docs: https://anyshake.org/docs/AnyShake%20Observer/Configuration/adc
Look at lines 54, 59, 64 in this file. main.cpp This is line 54, I'll paste it down here.
packet.EHZ[i] = EHZ.data >> 5;
I don't know why we're moving 5 bits to the right here. Because after my actual measurement, I found that this will lead to the actual measurement value smaller, will be smaller by 32 times.