spring环境读取inline表达式时报Could not resolve placeholder

wangjianwen commented 6 years ago

Please answer these questions before submitting your issue. Thanks!

Which version of Sharding-Jdbc do you using?

sharding-jdbc 2.0.1

Expected behavior

spring boot环境能读取inline表达式

Actual behavior

启动spring boot时 java.lang.IllegalArgumentException: Could not resolve placeholder '0..1' in value "db_${0..1}.receivedetail${[0, 5]}"

Steps to reproduce the behavior

由于项目需求，需要自定义sharding配置文件，自己解析。所以在项目的application.properties文件中，配置sharding规则: xxx.datasource.sharding.tablerule.names=tablerule1 xxx.datasource.sharding.tablerule1.logictable=t1 xxx.datasource.sharding.tablerule1.actualDataNodes=db${0..1}.t1${[0, 5]} xxx.datasource.sharding.tablerule1.databaseShardingStrategyType=standard xxx.datasource.sharding.tablerule1.databaseShardingStrategy.shardingColumn=id xxx.datasource.sharding.tablerule1.databaseShardingStrategy.preciseAlgorithmClassName=ModuloDatabaseShardingAlgorithm xxx.datasource.sharding.tablerule1.tableShardingStrategyType=complex xxx.datasource.sharding.tablerule1.tableShardingStrategy.shardingColumns=name,id xxx.datasource.sharding.tablerule1.tableShardingStrategy.algorithmClassName=ModuloTableShardingAlgorithm

按照FAQ 2中所说，我添加了如下bean配置

       @Bean
        public PropertySourcesPlaceholderConfigurer propertySourcesPlaceholderConfigurer() {
            PropertySourcesPlaceholderConfigurer p = new PropertySourcesPlaceholderConfigurer();
            p.setLocations(new ClassPathResource("application.properties"));
            p.setIgnoreUnresolvablePlaceholders(true);
            return p;
        }

Please provide the reproduce example codes (such as github link) if possible.

terrymanu commented 6 years ago

请参考example https://github.com/shardingjdbc/sharding-jdbc-example/tree/dev/sharding-jdbc-spring-boot-example/sharding-jdbc-spring-boot-data-mybatis-example

wgou commented 6 years ago

请问不使用spring boot 呢？在properties中配置 xxx.datasource.sharding.tablerule1.actualDataNodes=db${0..1}.t1${[0, 5]}

在spring.xml 中使用 ${xxx.datasource.sharding.tablerule1.actualDataNodes} 出错怎么处理？

能不能把解析器中 $ 判断换成别的

Bughue commented 1 year ago

请参考example https://github.com/shardingjdbc/sharding-jdbc-example/tree/dev/sharding-jdbc-spring-boot-example/sharding-jdbc-spring-boot-data-mybatis-example

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