Open CoderWeiLee opened 7 months ago
在Controller中处理Request时，似乎前面有await方法处理，就会返回这个服务器内部错误。 Future call(Request request) async { var method = request.method; print("method是$method"); if (method == "GET") { // var body = await request.body; // var json = body.json; var path = await request.url.path; switch (path) { case 'intranetIP': SharedPreferences prefs = await SharedPreferences.getInstance(); var ipv4 = prefs.get('ipv4') as String; print("ipv4是$ipv4"); if (ipv4 != null && ipv4.isNotEmpty) { print("返回ipv4地址"); return Response.ok("11"); }else { return Response.notFound('ip地址获取失败，请刷新重试'); }
在Controller中处理Request时，似乎前面有await方法处理，就会返回这个服务器内部错误。 Future call(Request request) async {
var method = request.method;
print("method是$method");
if (method == "GET") {
// var body = await request.body;
// var json = body.json;
var path = await request.url.path;
switch (path) {
case 'intranetIP':
SharedPreferences prefs = await SharedPreferences.getInstance();
var ipv4 = prefs.get('ipv4') as String;
print("ipv4是$ipv4");
if (ipv4 != null && ipv4.isNotEmpty) {
print("返回ipv4地址");
return Response.ok("11");
}else {
return Response.notFound('ip地址获取失败，请刷新重试');
}