search

arkmanager / ark-server-tools

Set of server tools used to manage ARK: Survival Evolved servers on Linux
MIT License
684 stars 144 forks source link

Right way to install mods on a cluster setup #1092

Open staddecx opened 4 years ago

staddecx commented 4 years ago

Hello,

we are currently running 7 maps/instances on one dedicated server and I'm trying to figure out the right way to install mods.

We have about 17mods we want to use. I used to put all the IDs into the instances config files and then arkmanager installmods @all, but removing or installing another mods makes it a bit annoying in the long run, putting the ID into every single instance config.

I was thinking about to remove all mods which are currently listed in the instance configs (put comment on the ark_GameModIds line), then arkmanager uninstallmod id1,id2,id3 @all (all the IDs from the instance config) and then reinstall the mods I want with arkmanager installmod id1,id2,id3 @all.

Would this be the right way to have it cleaner and easier?

Thanks!

klightspeed commented 4 years ago

If a mod is shared between all of the instances, you should be able to use arkmod_{modid}=enabled in your arkmanager.cfg

Alternatively, you can use arkmanager enablemod {modid} @all to write this option to all of the instance configs.

staddecx commented 4 years ago

Oh I see, so its enough to put it into the .arkmanager.cfg instead of each instace since yeah we share all the mods with all the instances.

So I can comment the ark_GameModIds={modids} in each instance and put it into the .arkmanager.cfg?

klightspeed commented 4 years ago

Oh I see, so its enough to put it into the .arkmanager.cfg instead of each instace since yeah we share all the mods with all the instances.

So I can comment the ark_GameModIds={modids} in each instance and put it into the .arkmanager.cfg?

Yes. As long as there are no options that need to be at the end of the server options string (options in arkmanager.cfg or .arkmanager.cfg will go onto the end of the server options string, usually in ASCIIbetical order), this should work.