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arnaud-m / cryptator

A constraint-based cryptarithm solver
BSD 3-Clause "New" or "Revised" License
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Reject && at the end of cryptarithms and multiple && side by side #134

Closed FissoreD closed 1 year ago

FissoreD commented 1 year ago

  1. The parser should not accept a cryptarithm having the && operator at the end of it. Example: a + b = c && -> should be rejected a + b = c; -> should be accepted

  2. The parser should not accept multiple && side by side Example: a + b = c &&&& a + c = d -> should be rejected