Closed blue-ringed-octopus closed 8 months ago
directly from the paper.
Where did you find the formula that you posted?
thank you for the reply, i found it on here https://github.com/artivis/manif/blob/devel/paper/Lie_theory_cheat_sheet.pdf
the right jacobian of right- $\ominus $
Nice catch! We'll fix it, thank you!
@artivis would you take care of this fix? I am not sure if I have access to the latex sources
@artivis I did change the latex sources in overleaf. However the version there and the one on github are quite different. So I did not push the changes here. I let you do it.
FYI: In the sources, I re-defined \bfMx
and \bfMy
to produce \mathcal{X}
and \mathcal{Y}
respectively, as in the paper.
Thanks for the ping.
I'll update the pdf asap :+1:.
the jacobian shows $J^{\mathcal{\gamma}\ominus\mathcal{\chi}}_{\tau} = J_r^{-1}(\tau)$
is it supposed to mean $J^{\mathcal{\gamma}\ominus\mathcal{\chi}}_{\mathcal{\gamma}} = J_r^{-1}(\tau)$ ?
I assume $\tau = \mathcal{\gamma} \ominus \mathcal{\chi}$