Closed GenevaS closed 6 years ago
I agree. However, in the case of this example, x0
is provided and x(t0)
is what one wants know.
Shouldn't your symbol for this definition be x(t0)
then? If I take the same original example, you state that the symbol is x0
but then define the equation as x(t0) = x0
. My confusion is in what you are calling your "symbol" for the definition.
Good question. I wrote it up the way most sources seem to - I think that's because x(t0)
could hypothetically be assigned different x0
's, since we only know x'
, and not x
. (Intuitively, since we often need to add a + C when integrating, there could be multiple solutions for different values of C.)
@smiths, what do you think the right thing to do is in this case?
I'm not sure what the question is here. If LHS = RHS, then RHS = LHS. The symbols are x, t0 and x0. x has type real to real, t0 is real and x0 is real. Stylistically, I prefer x(t0) = x0, but it isn't a strong preference.
I've left it as is as this seems more a matter of personal taste.
Ok, fair enough.
I would ask Dr. Smith about this one first:
Shouldn't the equations be written such that the symbol being defined is the LHS and the equation that it can be found with is the RHS?
A trivial example: instead of writing
x(t0) = x0
for Initial values (x0
), writex0 = x(t0)
.