asmcrypto / asmcrypto.js

JavaScript Cryptographic Library with performance in mind.
MIT License
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RSA PKCS#1 v1.5 signature scheme verification incompatibility issue #182

Open yahyazadeh opened 3 years ago

yahyazadeh commented 3 years ago

I was testing PKCS#1 v1.5 signature verification as implemented in asmcrypto and noticed it rejects valid signature whose encoded message uses an implicit NULL parameter for hash algorithm (where digestAlgorithm ANS.1 der encoded does not have NULL parameter TLV; that is, 0x0500 is absent). According to RFC4055, pg.5 and RFC8017, pg. 64, for SHA-1, and the SHA-2 family, the algorithm parameter has to be NULL and both explicit NULL parameter and implicit NULL parameter (ie, absent NULL parameter) are considered to be legal and equivalent. However, this implementation does not accept a valid PKCS input with implicit NULL parameter.

Reference notation and concrete values

N = 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

|N| = 256 bytes

d = 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

e = 3

H = SHA-256 (OID = 0x608648016503040201)

m = "hello world!"

I = 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

S = 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
Gonzalo2683 commented 3 years ago

@yahyazadeh I am having a similar problem, have you found an alternative for this case?